英文:
Check the size of tkinter window using "if" statement
问题
if root.geometry == "457x450":
print("窗口大小为457x450像素！")
else:
print("窗口大小不是457x450！")
英文:
I want an if-function to check the geometry of a window in python (tkinter).
This is what I've got, but it doesn't work:
if root.geometry == "457x450":
print("The window is 457x450 pixels!")
else:
print("The window is not 457x450!")
root = Tk()
root.geometry("300x300")
root.mainloop()
In this case it should print "The window is not 457x450!"
答案1
得分: 3
以下是翻译好的部分：
条件 if root.geometry == "457x450": 将永远不会为真。 root.geometry 是一个绑定的方法，你将其与一个字符串进行比较。你需要像这样调用它 root.geometry() 以从 tkinter 中检索几何字符串。
然而，几何字符串的格式是 widthxheight+x+y，所以即使你拥有正确的 width 和 height，你的条件仍然不会变为 True。
一个简单的方法是：
if root.geometry().split('+')[0] == "457x450":
英文:
The condition if root.geometry == "457x450": will never be true. root.geometry is a bound method that you compare to a string. You will need to call it like root.geometry() to retrieve the geometry string from tkinter.
However a geometry string has the form of widthxheight+x+y So your condition will still not turn to True even you have the right width and height.
A simple way of doing it would be:
if root.geometry().split('+')[0] == "457x450":
答案2
得分: 1
你可以使用 root.winfo_height() 和 root.winfo_width() 来查询窗口的当前宽度和高度（以像素为单位）。
请注意，如果在启动应用程序后立即调用这些方法（即通过调用 root.mainloop()），你将得到错误的数字，因为窗口尺寸尚未建立，所以在调用 winfo_ 方法之前应该调用 root.update_idletasks()！
这应该是你想要的效果：
root.update_idletasks() # 确保窗口已更新
width, height = root.winfo_width(), root.winfo_height() # 获取窗口尺寸
if (width, height) == (457, 450):
print("窗口尺寸为 457x450 像素！")
else:
print("窗口尺寸不是 457x450 像素！")
英文:
You can use root.winfo_height() and root.winfo_width() to query the current width and height of the window in pixels.
Note that if you call these methods immediately after starting your app (i.e., by calling root.mainloop()) you'll get erroneous numbers because the window size hasn't been established yet, so you should call root.update_idletasks() before the call(s) to the winfo_ methods!
This should to what you want:
root.update_idletasks() # make sure the window is up to date
width, height = root.winfo_width(), root.winfo_height() # get the window dimensions
if (width, height) == (457, 450):
print("The window is 457x450 pixels!")
else:
print("The window is not 457x450!")
答案3
得分: 0
Hi guys，我弄清楚了！我只需要将窗口的实际大小存储在一个变量中...
root = Tk()
size = "304x450"
root.geometry(size)
root.mainloop()
然后只需说...
if size == "457x450":
print("Hello World")
对我来说有效。如果我在函数中使用它，我只需将变量全局化。
英文:
Hi guys I figured it out! I just have to store the actual size of the window in a variable....
root = Tk()
size = "304x450"
root.geometry(size)
root.mainloop()
and then just say..
if size == "457x450":
print("Hello World")
Worked for me. I just had to globalize the variable if I'm using it in a function.
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