英文:
How to convert time data which saved as integer type in csv file into datetime in python
问题
import pandas as pd# Assuming df_NPA_2020 is your DataFrame and 'TIME' is the column with integer time datadf_NPA_2020['ch_time'] = df_NPA_2020['TIME'].apply(lambda x: '{:02d}:{:02d}:{:02d}'.format(x // 3600, (x % 3600) // 60, x % 60))
使用上述代码片段，您可以将整数类型的时间数据转换为日期时间格式，将结果存储在名为'ch_time'的新列中。
英文:
I have csv file and in 'Time' column, time data is saved in integer type like
7201324321123456...
and I have to convert datatime in python like
00:00:0700:00:2000:01:3200:43:2112:34:56...
and size of data is almost 250,000,,,
How do I convert this number to a datetime?
I tried but failed
change_time=str(int(df_NPA_2020['TIME'])).zfill(6)change_time=change_time[:2]+":"+change_time[2:4]+":"+change_time[4:]change_time
and
change_time=df_NPA_2020['ch_time'] = df_NPA_2020['TIME'].apply(lambda x: pd.to_datetime(str(x), format='%H:%M:%S'))
答案1
得分: 4
你差不多到了。你需要使用.astype(str)方法将一个列转换为字符串，而不是str(df_NPA_2020['TIME'])。后者类似于print。
df_NPA_2020['ch_time'] = pd.to_datetime(df_NPA_2020['TIME'].astype(str).str.zfill(6), format='%H%M%S').dt.timeprint(df_NPA_2020)# 输出TIME ch_time0 7 1900-01-01 00:00:071 20 1900-01-01 00:00:202 132 1900-01-01 00:01:323 4321 1900-01-01 00:43:214 123456 1900-01-01 12:34:56
英文:
You're almost there. You have to use .astype(str) method to convert a column as string and not str(df_NPA_2020['TIME']). The latter is like a print.
df_NPA_2020['ch_time'] = pd.to_datetime(df_NPA_2020['TIME'].astype(str).str.zfill(6), format='%H%M%S').dt.timeprint(df_NPA_2020)# OutputTIME ch_time0 7 1900-01-01 00:00:071 20 1900-01-01 00:00:202 132 1900-01-01 00:01:323 4321 1900-01-01 00:43:214 123456 1900-01-01 12:34:56
答案2
得分: 2
将数字解析为日期时间，然后格式化它：
import pandas as pddf = pd.DataFrame([7, 20, 132, 4321, 123456], columns=['Time'])print(df)df.Time = df.Time.apply(lambda x: pd.to_datetime(f'{x:06}', format='%H%M%S')).dt.strftime('%H:%M:%S')print(df)
输出：
Time0 71 202 1323 43214 123456Time0 00:00:071 00:00:202 00:01:323 00:43:214 12:34:56
英文:
Parse the number into a datetime, then format it:
import pandas as pddf = pd.DataFrame([7,20,132,4321,123456], columns=['Time'])print(df)df.Time = df.Time.apply(lambda x: pd.to_datetime(f'{x:06}', format='%H%M%S')).dt.strftime('%H:%M:%S')print(df)
Output:
Time0 71 202 1323 43214 123456Time0 00:00:071 00:00:202 00:01:323 00:43:214 12:34:56
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