英文:
Using filter in makefile to run other make targets
问题
我正在尝试简化我的makefile，允许使用过滤器（%）的目标来捕获我希望其他目标具有扩展操作的时机。
一个示例是：
1-check:
echo "1"
2-check:
echo "2"
run-check:
1-check-all 2-check-all
%-all:
echo $*
这能够打印出2个目标的名称，分别为1-check和2-check。我原本期望，如果我在%-all中去掉echo，它会运行捕获的目标。
当我调用1-check-all时，我期望修改后的%-all - 如下所示 - 会调用该方法：
%-all:
$*
这时$*的值将是"1-check"，然后运行该目标，我会看到"echo 1"被执行。
我对makefile还不够了解，尚未找到类似这样做的示例。
英文:
I am trying to simplify my makefile by allowing a target with a filter (%) to capture when I want other targets to have expanded actions
An example of this would be
1-check:
echo "1"
2-check:
echo "2"
run-check:
1-check-all 2-check-all
%-all:
echo $*
This is able to print the 2 targets names as 1-check and 2-check and I was expecting that if I remove the echo in %-all it would run the captured target
What I would expect when I call 1-check-all is that the modified %-all - seen below - it would invoke the method
%-all:
$*
Would have "1-check" as the value of $* and it would then run that target and I would see "echo 1" executed.
I am new to makefiles and haven't been able to find an example doing something similar to this.
答案1
得分: 1
以下是翻译的部分：
一些问题。这个：
%-all:
$*
在你的 makefile 中并不存在。最接近的是这个：
%-all:
echo $*
但是这两者都不会调用另一个规则。为了达到我认为你想要的效果，你必须将%列为规则的先决条件：
%-all: %
echo $*
英文:
A couple of problems. This:
%-all:
$*
does not appear in your makefile. The nearest thing to it is this:
%-all:
echo $*
But neither of these will invoke another rule. To get the effect I think you want, you must list % as a prerequisite of the rule:
%-all: %
echo $*
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