英文:
Python declaring multiple values in a single variable in a class
问题
isSolvable()
函数应该在计算结果为0时返回False
。
英文:
I'm trying to call the values that I have inputted into the function solvable. It's not returning a boolean value in response to the input. This is my code:
class CramersRule:
a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 = eval(input("Please enter values a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 of a simultaneous eq: "))
def __init__(self):
self.__a1 = a1
self.__a2 = a2
self.__a3 = a3
self.__b1 = b1
self.__b2 = b2
self.__b3 = b3
self.__c1 = c1
self.__c2 = c2
self.__c3 = c3
self.__d1 = d1
self.__d2 = d2
self.__d3 = d3
def isSolvable(self, a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3):
if (a1*b2*c3 - a1*b3*c2 -a2*b1*c3 + a2*b3*c1 + a3*b1*c2 - a3*b2*c1) != 0:
return True
else:
return False
The isSolvable()
function is supposed to return False
if the method calculates the value to be 0.
答案1
得分: 0
欢迎来到Stack Overflow!
尝试这个。
class CramersRule:
def __init__(self):
a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 = eval(input("请输入方程组的系数 a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3: "))
self.__a1 = a1
self.__a2 = a2
self.__a3 = a3
self.__b1 = b1
self.__b2 = b2
self.__b3 = b3
self.__c1 = c1
self.__c2 = c2
self.__c3 = c3
self.__d1 = d1
self.__d2 = d2
self.__d3 = d3
def isSolvable(self):
if (self.__a1*self.__b2*self.__c2 - self.__a1*self.__b3*self.__c2 -self.__a2*self.__b1*self.__c3 + self.__a2*self.__b3*self.__c1 + self.__a3*self.__b1*self.__c2 - self.__a3*self.__b2*self.__c1) != 0:
return True
else:
return False
我不确定你在哪里或者如何运行你的函数,但是我能够将代码保存到一个名为 fq.py
的文件中,并在Python REPL中进行验证。
>python
>>>import fq
接下来,创建一个CramersRule类的实例并将其赋给变量f。在提示符中输入数字。
>>>f = fq.CramersRule()
最后,根据你输入的数字看它是True还是False。
>>>f.isSolvable()
英文:
welcome to Stack Overflow!
Try this.
class CramersRule:
def __init__(self):
a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 = eval(input("Please enter values a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 of a simultaneous eq: "))
self.__a1 = a1
self.__a2 = a2
self.__a3 = a3
self.__b1 = b1
self.__b2 = b2
self.__b3 = b3
self.__c1 = c1
self.__c2 = c2
self.__c3 = c3
self.__d1 = d1
self.__d2 = d2
self.__d3 = d3
def isSolvable(self):
if (self.__a1*self.__b2*self.__c2 - self.__a1*self.__b3*self.__c2 -self.__a2*self.__b1*self.__c3 + self.__a2*self.__b3*self.__c1 + self.__a3*self.__b1*self.__c2 - self.__a3*self.__b2*self.__c1) != 0:
return True
else:
return False
I'm not sure how or where you're running your function but I was able to save the code to a file name fq.py
and this is how I verified it in the python repl.
>python
>>>import fq
Next create an instance of the CramersRule class and assign it to a variable f. Also input the numbers at the prompt.
>>>f = fq.CramersRule()
Finally, see if it's true or false based on the numbers you input.
>>>f.isSolvable()
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论