How can I omit records when returning a table in postgresql?

I have a problem when I try to execute a function where, depending on the result of another function, it returns a record or not. What I want to do is that when the function ("function_typecar" in the example) returns 1 as a result, it returns the record, otherwise no. The problem is when the condition is not met. It repeats the same record until there is one that meets the condition again. Is there a way to skip returning the records when the condition is not met? I leave an example of this situation

CREATE OR REPLACE FUNCTION schema.function_test
  RETURNS TABLE(id_r INTEGER, name_r CHARACTER VARYING, year_r INTEGER) AS
$BODY$
  
DECLARE 
	sql_record RECORD;
	type_car INTEGER;
BEGIN  
	SELECT id, name, year
	FROM car
	FOR sql_record IN
		SELECT id, name, year
		FROM car
	LOOP
		SELECT type INTO type_car FROM function_typecar(sql_record.id);
		IF type_car = 1 THEN
			id_r := sql_record.id;
			name_r := sql_record.name;
			year_r := sql_record.year;			
		END IF;
		RETURN NEXT;
	END LOOP;
END; $BODY$

This is the result that I want to avoid and that only brings me those that meet the IF condition:

Something like this should work, without a LOOP and in plain SQL:

CREATE OR REPLACE FUNCTION function_test()
  RETURNS TABLE(id_r INTEGER, name_r CHARACTER VARYING, year_r INTEGER)
LANGUAGE SQL 
	AS
$BODY$
    SELECT  id, name, year
    FROM car
			JOIN function_typecar(id) ON type = 1;
$BODY$;