sort dictionary alphabetically by key in odoo 13

I have built a dictionary to collect orders according to the client, the products that have been ordered and I need to order it alphabetically by client to use it in a qweb report, nothing I have tried so far has worked for me. Any ideas?

reparto_data = {
    'Cliente 1': {
       'Pastel manzana': 12,
       'Bomba crema': 8,
    },

    'Cliente 2': {
       'Cake calabaza': 18,
       'Bombon chocolate': 8,
    },

    #...
}

reparto_data2 = {}
for i in sorted(reparto_data[key]):
    reparto_data2[i] = reparto_data[i]

You need to sort the inner dictionaries.

So, iterate across the keys and values of the outer dict, and for each value (which is an inner dict), sort it.

from pprint import pprint

reparto_data = {
    'Cliente 1': {
        'Pastel manzana': 12,
        'Bomba crema': 8,
    },

    'Cliente 2': {
        'Cake calabaza': 18,
        'Bombon chocolate': 8,
    },
}

def sort_dict(d):
    return {k: d[k] for k in sorted(d.keys())}

reparto_data2 = {k: sort_dict(v) for k,v in reparto_data.items()}
pprint(reparto_data2, width=1)

Output

{'Cliente 1': {'Bomba crema': 8,
               'Pastel manzana': 12},
 'Cliente 2': {'Bombon chocolate': 8,
               'Cake calabaza': 18}}

You can try this too.

reparto_data = {
    'Cliente 1': {
        'Pastel manzana': 12,
        'Bomba crema': 8,
    },
    'Cliente 2': {
        'Cake calabaza': 18,
        'Bombon chocolate': 8,
    },
}

sorted_clients = sorted(reparto_data.keys(), key=lambda x:x.lower())

reparto_data2 = {i: reparto_data[i] for i in sorted_clients}

Output

{'Cliente 1': {'Pastel manzana': 12, 'Bomba crema': 8}, 'Cliente 2': {'Cake calabaza': 18, 'Bombon chocolate': 8}}

If want to use your own code just replace this with your loop

reparto_data2 = {i: reparto_data[i] for i in sorted(reparto_data[key])}

Thanks for your help but I have posed the question wrong since the dictionary contains objects.

The code that has worked for me is the following:

reparto_data2 = sorted(reparto_data.items(), key=lambda x: x[0].lower())