英文:
Doesnt compare list's correctly
问题
def split(word):
x = list(word)
return x
whitelist = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P']
word = input('Password ')
split(word)
x = split(word)
if not all(letter in whitelist for letter in x):
print('Incorrect letters')
else:
print('Correct')
英文:
def split(word):
x = list(word)
return x
whitelist = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
word = input('Password ')
split(word)
x = split(word)
if x not in whitelist:
print('Incorrect letters')
else:
print('Correct ')
When i enter FECHCH for eks. , 'if' keeps giving me communicate - inncorrect letters .
I need python3 to understand, that letters FECHCH are in whitelist.
答案1
得分: 0
您需要逐个输入字母
def split(word):
x = list(word)
return x
whitelist = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
word = input('密码 ')
split(word)
x = split(word)
print(x)
# 密码 FECHCH
['F', 'E', 'C', 'H', 'C', 'H']
所以您正在比较：
['F', 'E', 'C', 'H', 'C', 'H'] 在 ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
这是 False
正如评论中所提到的，您可以使用 set() 来去除重复并检查子集。
word = input('密码 ')
split(word)
x = split(word)
if set(x).issubset(whitelist):
print('正确 ')
else:
print('不正确的字母')
英文:
You need to enter letters one by one
def split(word):
x = list(word)
return x
whitelist = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
word = input('Password ')
split(word)
x = split(word)
print(x)
#Password FECHCH
['F', 'E', 'C', 'H', 'C', 'H']
so you are comparing:
['F', 'E', 'C', 'H', 'C', 'H'] in ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
which is False
as mentioned in comments, you can use a set() to remove duplicates and check subsets.
word = input('Password ')
split(word)
x = split(word)
if set(x).issubset(whitelist):
print('Correct ')
else:
print('Incorrect letters')
答案2
得分: 0
无需特殊的拆分函数。您可以简单地使用（假设您接受小写字母要被转换，否则省略upper()函数）：
whitelist = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P']
word = input('密码 ')
# 对每个字符进行报告
for ch in word.upper():
if ch not in whitelist:
print('不正确的字母', ch)
else:
print('正确的字母', ch)
# 或者检查整个单词
for ch in word.upper():
if ch not in whitelist:
val = '不正确的字母'
break
else:
val = '正确的字母'
print(val)
英文:
No special split function is required. You could simply use (assuming you accept lower case letters to be converted else omit upper():
whitelist = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P']
word = input('Password ')
# to report on each character
for ch in word.upper():
if ch not in whitelist:
print('Incorrect letter', ch)
else:
print('Correct letter', ch)
# or to check the whole word
for ch in word.upper():
if ch not in whitelist:
val = 'Incorrect letters'
break
else:
val = 'correct letters'
print(val)
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