英文:
find the sum of the digits of the integer part of the number and the multiplication of the digits of the fractional part of the number
问题
整数部分的数字之和以及小数部分的数字之积。我只能输出整数部分的答案。
英文:
find the sum of the digits of the integer part of the number and the multiplication of the digits of the fractional part of the number.
I can only output the answer to the integer part of the number.
答案1
得分: 1
只返回翻译好的部分,不包括代码:
-
将数字分成整数部分和小数部分:
可以使用内置的divmod
函数。例如,divmod(7.86, 1)
返回(7, 0.86)
。 -
找到整数部分的数字之和。可以用多种方法来实现,性能有所不同。可以将整数部分转换为字符串,然后迭代字符串的字符并将值添加到一个变量中。
-
类似地,可以将小数部分转换为小数点后的字符串,然后迭代字符串的字符并将值与一个变量相乘。
-
返回上述步骤的两个结果。
英文:
You didn't show us what you tried, so i'll give you only some steps and leave the implementation for you to do by yourself.
-
Split the number into integer and fractional parts:
You can use the built-indivmod
function. For example,divmod(7.86, 1)
returns(7, 0.86)
. -
Find the sum of the digits of the integer part. This can be done in multiple ways with varying performance.You can convert the integer part to a string, then iterate over the characters of the string and add the values to a variable.
-
Similarly, you can convert the fractional part to a string after the decimal point, then iterate over the characters of the string and multiply the values with a variable.
-
Return the two results of the steps above.
Edit: The code you posted in the comment can be fixed as follows. You want to escape the iteration when hitting the .
symbol, and make the check first because the user might enter .456
.
s = input()
letsGo = summa = 0
proizved = 1
for i in s:
if i == ".":
letsGo = 1
continue
if letsGo == 1:
proizved *= int(i)
else:
summa += int(i)
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