如何防止在Android中显示多个DialogFragments？

huangapple
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英文:

How to prevent showing multiple DialogFragments in Android?

问题

我在我的Android应用程序中有一些自定义的DialogFragments。我想要防止用户打开多个对话框，同时避免禁用显示对话框的按钮一次按下后或使用变量。

所以我尝试为片段制作一个扩展，通过它们的标签来检查显示的片段，就像这样：

  1. fun Fragment.isFragmentVisible(tag: String): Boolean {
  2.     val fragment = childFragmentManager.findFragmentByTag(tag)
  3.     if (fragment != null && fragment.isVisible) {
  4.         return true
  5.     }
  6.     return false
  7. }

在显示对话框之前进行检查，就像这样：

  1. binding.destination.editText?.setOnClickListener {
  2.     if (!isFragmentVisible(ShopsDialog.TAG)) {
  3.         ShopsDialog.newInstance(this, "Destinazione") { bundle ->
  4.             val shopId = bundle.getString("shopId")
  5.             viewModel.setDestination(shopId)
  6.         }
  7.     }
  8. }

而newInstance函数如下：

  1. fun newInstance(fragment: Fragment, title: String, bundle: (Bundle) -> Unit) = ShopsDialog().apply {
  2.     arguments = Bundle().apply {
  3.         putString(ARG_TITLE, title)
  4.     }
  6.     fragment.setFragmentResultListener(KEY_CALLBACK_BUNDLE) { requestKey: String, bundle: Bundle ->
  7.         if (requestKey == KEY_CALLBACK_BUNDLE) {
  8.             bundle(bundle)
  9.         }
  10.     }
  11.     show(fragment.childFragmentManager, TAG)
  12. }

但是这似乎不起作用，我甚至尝试使用requireActivity().supportFragmentManager而不是childFragmentManager，但仍然没有效果...

英文:

I have some custom DialogFragments in my Android application. I would prevent the user from opening multiple dialogs, and I would also avoid disabling the button which shows the dialog once it's pressed or using a variable or it.

So I was trying to make an extension for the fragment which checks for shown fragments via their tags like this:

  1. fun Fragment.isFragmentVisible(tag: String): Boolean {
  2.     val fragment = childFragmentManager.findFragmentByTag(tag)
  3.     if (fragment != null && fragment.isVisible) {
  4.         return true
  5.     }
  6.     return false
  7. }

And before showing the dialog to check it like this:

  1.     binding.destination.editText?.setOnClickListener {
  2.         if (!isFragmentVisible(ShopsDialog.TAG)) {
  3.             ShopsDialog.newInstance(this, "Destinazione") { bundle ->
  4.                 val shopId = bundle.getString("shopId")
  5.                 viewModel.setDestination(shopId)
  6.             }
  7.         }
  8.     }

While the newInstance is:

  1.    fun newInstance(fragment: Fragment, title: String, bundle: (Bundle) -> Unit) = ShopsDialog().apply {
  2.         arguments = Bundle().apply {
  3.             putString(ARG_TITLE, title)
  4.         }
  6.         fragment.setFragmentResultListener(KEY_CALLBACK_BUNDLE) { requestKey: String, bundle: Bundle ->
  7.             if (requestKey == KEY_CALLBACK_BUNDLE) {
  8.                 bundle(bundle)
  9.             }
  10.         }
  11.         show(fragment.childFragmentManager, TAG)
  12.     }

But this seems not to work, I've tried even to use requireActivity().supportFragmentManager instead childFragmentManager but still nothing...

答案1

得分: 1

在显示底部对话框片段之前，我认为你可以像这样检查它

  1. if (childFragmentManager.findFragmentByTag(ShopsDialog::class.java.simpleName) == null) {
  2.    // 显示你的底部对话框片段
  3. }

如果你要在 Fragment 中显示 BottomSheetDialogFragment，那么请使用 childFragmentManager，如果在 Activity 中显示，则使用 supportFragmentManager。

英文:

Before showing bottomsheetdialogfragment , i think you can check it like this

  1. if(childFragmentManager.findFragmentByTag(ShopsDialog::class.java.simpleName) == null){
  2.    // show your bottom sheet dialog fragment
  3.   
  4. }

If you are going to show bottomSheetDialogFragment in Fragment then use childFragmentManager and if it is activity then use supportFragmentManager

huangapple
  • 本文由 发表于 2023年2月8日 19:36:01
  • 转载请务必保留本文链接：https://go.coder-hub.com/75385219.html
  • android
  • kotlin
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