问题

{
   "@serviceName": "75MultipleService",
   "inputs": [
      {
        "@name": "inp1",
        "value": "8",
        "@type": "number"
      },
      {
       "@name": "inp2",
       "value": "8",
       "@type": "number"
     }
   ]
}

你可以使用以下Java代码将嵌套的JSON数据传递为POST请求的主体：

import org.springframework.http.HttpEntity;
import org.springframework.http.HttpHeaders;
import org.springframework.http.MediaType;
import org.springframework.web.client.RestTemplate;

// 创建一个包含你的JSON数据的Map
Map<String, Object> requestBody = new HashMap<>();
requestBody.put("@serviceName", "75MultipleService");

List<Map<String, Object>> inputs = new ArrayList<>();
Map<String, Object> input1 = new HashMap<>();
input1.put("@name", "inp1");
input1.put("value", "8");
input1.put("@type", "number");
inputs.add(input1);

Map<String, Object> input2 = new HashMap<>();
input2.put("@name", "inp2");
input2.put("value", "8");
input2.put("@type", "number");
inputs.add(input2);

requestBody.put("inputs", inputs);

// 设置HTTP头部
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);

// 创建HTTP实体
HttpEntity<Map<String, Object>> requestEntity = new HttpEntity<>(requestBody, headers);

// 发送POST请求
RestTemplate restTemplate = new RestTemplate();
String url = "your_post_url_here";
String response = restTemplate.postForObject(url, requestEntity, String.class);

请确保替换 "your_post_url_here" 为你要发送POST请求的实际URL。这段代码会将你的JSON数据转化为HTTP请求体，并将其发送到指定的URL。

{
   "@serviceName": "75MultipleService",
   "inputs": [
          {
            "@name": "inp1",
            "value": "8",
            "@type": "number"
          },
          {
           "@name": "inp2",
           "value": "8",
           "@type": "number"
     }
   ]
}

	Map <String, Object> map = new HashMap<> ();
	map.put("@serviceName", "75MultipleService");
	map.put("inputs", Arrays.asList(new HashMap<String, Object>() {{
	    put("@name", "inp1");
	    put("value", "8");
	    put("@type", "number");
	}}));

答案1

得分: 0

如何传递 input2

这只是另一个 Map，你可以这样做。

Map<String, Object> input1 = Map.of("@name", "inp1", "value", "8", "@type", "number");
Map<String, Object> input2 = Map.of("@name", "inp2", "value", "8", "@type", "number");
Map<String, Object> payload = Map.of("@serviceName", "75MultipleService", "inputs", List.of(input1, input2));

Map<String, Object> input1 = Map.of("@name", "inp1", "value", "8", "@type", "number");
Map<String, Object> input2 = Map.of("@name", "inp2", "value", "8", "@type", "number");
Map<String, Object> payload = Map.of("@serviceName", "75MultipleService", "inputs", List.of(input1, input2));