英文:
Can't update is_active on user: user.update(is_active: true) fails
问题
user.update(is_active: true)在Rails控制台中有效，但在应用程序中无效。
这是来自sessions_controller.rb的代码：
def create
username_or_email = params[:session][:username_or_email].downcase
user = if username_or_email.include?("@")
User.find_by(email: username_or_email)
else
User.find_by(username: username_or_email)
end
if user && user.authenticate(params[:session][:password])
session[:user_id] = user.id
user.update!(is_active: true)
redirect_to user_path(user.username)
else
flash.now[:danger] = 'Invalid email/password combination'
render 'sign_in'
end
end
我得到以下结果：
Validation failed: Password can't be blank, Password is too short (minimum is 6 characters)
这似乎很奇怪，密码也应该传递吗？
英文:
user.update(is_active: true) works in the rails console, but not in the application.
This is from the sessions_controller.rb:
def create
username_or_email = params[:session][:username_or_email].downcase
user = if username_or_email.include?("@")
User.find_by(email: username_or_email)
else
User.find_by(username: username_or_email)
end
if user && user.authenticate(params[:session][:password])
session[:user_id] = user.id
user.update!(is_active: true)
redirect_to user_path(user.username)
else
flash.now[:danger] = 'Invalid email/password combination'
render 'sign_in'
end
end
I get this result:
Validation failed: Password can't be blank, Password is too short (minimum is 6 characters)
Which seems strange, is the password supposed to be passed too?
答案1
得分: 0
解决方案是使用 update_columns 而不是绕过验证。
这是因为用户模型有以下验证：
validates :password, presence: true, length: { minimum: 6 }
我在用户模型中添加了 sign_in 和 sign_out 函数，并在这些函数中正确处理了它。
英文:
The solution was to bypass validation using update_columns instead.
This was because the user model had this validation:
validates :password, presence: true, length: { minimum: 6 }
I added sign_in and sign_out functions to the user model and handled it properly in those.
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