英文:
Appending to lists within loops in Python3 (again)
问题
我在逐步向列表中添加元素时遇到了困难。
这是一个最小化工作示例(MWE):
# 给定一个嵌套的值列表或集合
sets = [[1, 2, 3], [1, 2, 4], [1, 2, 5]]
# 将一个值添加到每个子列表,表示该集合在列表中的编号。
n_sets = len(sets)
for s in range(n_sets):
(sets展开收缩).insert(0, s)
# 现在重复这些集合reps次
reps = 4
expanded_sets = [item for item in sets for i in range(reps)]
# 然后为每个集合的每次出现分配一个重复编号。
rep_list = list(range(reps)) * n_sets
for i in range(n_sets * reps):
(expanded_sets[i]).insert(0, rep_list[i])
expanded_sets
这段代码返回的结果是:
[[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5]]
而不是期望的结果:
[[0, 0, 1, 2, 3],
[1, 0, 1, 2, 3],
[2, 0, 1, 2, 3],
[3, 0, 1, 2, 3],
[0, 1, 1, 2, 4],
[1, 1, 1, 2, 4],
[2, 1, 1, 2, 4],
[3, 1, 1, 2, 4],
[0, 2, 1, 2, 5],
[1, 2, 1, 2, 5],
[2, 2, 1, 2, 5],
[3, 2, 1, 2, 5]]
希望这次的回答对你有所帮助。
英文:
I'm having difficulty adding to a list iteratively.
Here's a MWE:
# Given a nested list of values, or sets
sets = [[1, 2, 3], [1, 2, 4], [1, 2, 5]]
# add a value to each sublist giving the number of that set in the list.
n_sets = len(sets)
for s in range(n_sets):
(sets展开收缩).insert(0, s)
# Now repeat those sets reps times
reps = 4
expanded_sets = [item for item in sets for i in range(reps)]
# then assign a repetition number to each occurance of a set.
rep_list = list(range(reps)) * n_sets
for i in range(n_sets * reps):
(expanded_sets[i]).insert(0, rep_list[i])
expanded_sets
which returns
[[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 0, 1, 2, 3],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 1, 1, 2, 4],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5],
[3, 2, 1, 0, 2, 1, 2, 5]]
instead of the desired
[[0, 0, 1, 2, 3],
[1, 0, 1, 2, 3],
[2, 0, 1, 2, 3],
[3, 0, 1, 2, 3],
[0, 1, 1, 2, 4],
[1, 1, 1, 2, 4],
[2, 1, 1, 2, 4],
[3, 1, 1, 2, 4],
[0, 2, 1, 2, 5],
[1, 2, 1, 2, 5],
[2, 2, 1, 2, 5],
[3, 2, 1, 2, 5]]
Just for fun, the first loop returns an expected value of sets
[[0, 1, 2, 3], [1, 1, 2, 4], [2, 1, 2, 5]]
but after the second loop sets
changed to
[[3, 2, 1, 0, 0, 1, 2, 3], [3, 2, 1, 0, 1, 1, 2, 4], [3, 2, 1, 0, 2, 1, 2, 5]]
I suspect the issue has something to do with copies and references. I've tried adding .copy()
and slices in various places, but with the indexed sublists I haven't come across a combo that works. I'm running Python 3.10.6.
Thanks for looking!
Per suggested solution, [list(range(reps)) for _ in range(n_sets)]
doesn't correctly replace the list(range(reps)) * n_sets
, since it gives [[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]
instead of
the desired [0, 1, 2, 3, 0, 1, 2, 3, 0, 1, 2, 3]
. Do I need to flatten, or is there a syntax with the _
notation that gives me a single list?
Further update . . .
replacing
rep_list = list(range(reps)) * n_sets
with
rep_list_nest = [list(range(reps)) for _ in range(n_sets)]
rep_list = [i for sublist in rep_list_nest for i in sublist]
gives the same undesired result for expanded_sets
.
答案1
得分: 1
问题出在这里:
expanded_sets = [item
for item in sets
for i in range(reps)]
现在,这个列表中连续包含了sets
中的每个元素四次,然后是下一个元素重复四次,以此类推。
创建item
的副本可以修复这个问题:
expanded_sets = [item.copy()
for item in sets
for i in range(reps)]
如果你想要一个更符合Python风格的方法,那就认识到结果是两个范围的乘积,并且是你原始的sets
列表中所有元素的连接:
from itertools import product
sets = [[1, 2, 3], [1, 2, 4], [1, 2, 5]]
expanded_sets = [[inner_counter, outer_counter] + sets_elem
for sets_elem, outer_counter, inner_counter in product(sets, range(len(sets)), range(4))]
英文:
The problem is here:
expanded_sets = [item
for item in sets
for i in range(reps)]
This list now contains the same element of sets
four times in a row, followed by the next element repeated four times, and so on.
Creating copies of item
fixes the issue:
expanded_sets = [item.copy()
for item in sets
for i in range(reps)]
If you want a more pythonic approach, then recognize that the result is a product of two ranges, and your original sets
all concatenated together:
from itertools import product
sets = [[1, 2, 3], [1, 2, 4], [1, 2, 5]]
expanded_sets = [[inner_counter, outer_counter] + sets_elem
for sets_elem, outer_counter, inner_counter in product(sets, range(len(sets)), range(4))]
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