英文:
Convert complex comma-separated string into Python dictionary
问题
我从Pandas的CSV文件中获得了以下字符串格式：
> "title = matrix, genre = action, year = 2000, rate = 8"
如何将该字符串值更改为如下的Python字典：
movie = "title = matrix, genre = action, year = 2000, rate = 8"
movie = {
"title": "matrix",
"genre": "action",
"year": "2000",
"rate": "8"
}
英文:
I am getting following string format from csv file in Pandas
> "title = matrix, genre = action, year = 2000, rate = 8"
How can I change the string value into a python dictionary like this:
movie = "title = matrix, genre = action, year = 2000, rate = 8"movie = {"title": "matrix","genre": "action","year": "1964","rate":"8"}
答案1
得分: 1
你可以将字符串拆分，然后将其转换为字典。
以下是示例代码
movie = "title = matrix, genre = action, year = 2000, rate = 8"movie = movie.split(",")# print(movie)tempMovie = [i.split("=") for i in movie]movie = {}for i in tempMovie:movie[i[0].strip()] = i[1].strip()print(movie)
英文:
You can split the string and then convert it into a dictionary.
A sample code is given below
movie = "title = matrix, genre = action, year = 2000, rate = 8"movie = movie.split(",")# print(movie)tempMovie = [i.split("=") for i in movie]movie = {}for i in tempMovie:movie[i[0].strip()] = i[1].strip()print(movie)
答案2
得分: 1
以下是翻译好的代码部分：
import reinput_user = "title = matrix, genre = action, year = 2000, rate = 8"# 创建用于匹配键值对的模式pattern = re.compile(r"(\w+) = ([\w,]+)" )# 在输入字符串中查找所有匹配项matches = pattern.findall(input_user)# 将匹配项转换为字典result = {key: value for key, value in matches}print(result)
结果：
{'title': 'matrix,', 'genre': 'action,', 'year': '2000,', 'rate': '8'}
希望这可以解决您的问题。
英文:
For the solution you can use regex
import reinput_user = "title = matrix, genre = action, year = 2000, rate = 8"# Create a pattern to match the key-value pairspattern = re.compile(r"(\w+) = ([\w,]+)" )# Find all matches in the input stringmatches = pattern.findall(input_user)# Convert the matches to a dictionaryresult = {key: value for key, value in matches}print(result)
The result:
{'title': 'matrix,', 'genre': 'action,', 'year': '2000,', 'rate': '8'}
I hope this can solve your problem.
答案3
得分: 0
movie = "title = matrix, genre = action, year = 2000, rate = 8"
dict_all_movies = {}
for idx in df.index:
str_movie = df.at[idx, str_movie_column]
movie_dict = dict(item.split(" = ") for item in str_movie.split(", "))
dict_all_movies[str(idx)] = movie_dict
英文:
movie = "title = matrix, genre = action, year = 2000, rate = 8"dict_all_movies = {}for idx in df.index:str_movie = df.at[idx, str_movie_column]movie_dict = dict(item.split(" = ") for item in str_movie.split(", "))dict_all_movies[str(idx)] = movie_dict
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