英文:
My list python code is producing a sum other than what is intended. Python
问题
我正在尝试编写一个程序，该程序接受用户输入的订单并将其转换为一个列表，然后根据列表中每个单词的数量生成一个总和。然而，我的代码一直产生一个不正确的总和。例如，如果我输入“Water Nachos Water Cheeseburger”，预期总和应为24，但我的代码得出答案为39。这是为什么，以及有可能的修复方法是什么？
x = input("What are your orders?")
orders = list(x.split())
sum = 0
for i in orders:
if i == "Nachos":
sum += 6
if i == "Pizza":
sum += 6
if i == "Water":
sum += 4
if i == "Cheeseburger":
sum += 10
else:
sum += 5
print(sum)
我期望得到总和为24，但实际得到的总和为39。
英文:
I am trying to code a program that take user input of orders and converts it to a list that I can then produce a sum based on the number of each word in the list. However, my code keeps producing a a sum that is not correct for the provided list. For example, if I enter Water Nachos Water Cheeseburger the intended sum is 24, but my code is producing 39 as the answer. Why is this and what is a potential fix?
x = input("What are your orders?")
orders = list(x.split())
sum = 0
for i in orders:
if i == "Nachos":
sum+=6
if i == "Pizza":
sum+=6
if i == "Water":
sum+=4
if i == "Cheeseburger":
sum+=10
else:
sum+=5
print(sum)
I expected a sum of 24, but got a sum of 39.
答案1
得分: 1
最后的else部分仅适用于条件i == "Cheeseburger"。所以对于所有其他条件，sum+=5都会执行。
你可以使用if else if简化：
x = input("你想要点什么？")
orders = list(x.split())
sum = 0
for i in orders:
if i == "Nachos":
sum += 6
elif i == "Pizza":
sum += 6
elif i == "Water":
sum += 4
elif i == "Cheeseburger":
sum += 10
else:
sum += 5
print(sum)
英文:
The last else part is only for the if condition i == "Cheeseburger"
So `sum+=5 will gets executed for all the other conditions.
You can just use if else if
x = input("What are your orders?")
orders = list(x.split())
sum = 0
for i in orders:
if i == "Nachos":
sum+=6
elif i == "Pizza":
sum+=6
elif i == "Water":
sum+=4
elif i == "Cheeseburger":
sum+=10
else:
sum+=5
print(sum)
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