我想从在SSMS中用于生成日期的递归中创建表格或视图。

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英文:

I want to create table or view from a recursion used to generate a date in ssms

问题

我编写了一个递归查询来生成日期列。我希望将这些日期存储为数据库中的表,但似乎找不到方法。

declare @startdate date = '2014-01-01';
declare @enddate date = '2023-12-31';
with calendar as
 (
 select @startdate as [orderDate]
 union all
 select DATEADD(dd,1,[orderdate])
 from calendar
 where DATEADD(dd,1,[orderdate])<= @enddate
 )
 select * from calendar
 option (maxrecursion 0);
英文:

I wrote a recursive query to generate a column pf dates. I want the dates to be stored as a table in a db but can't seem to find a way.

declare @startdate date = &#39;2014-01-01&#39;;
declare @enddate date = &#39;2023-12-31&#39;;
with calendar as
 (
 select @startdate as [orderDate]
 union all
 select DATEADD(dd,1,[orderdate])
 from calendar
 where DATEADD(dd,1,[orderdate])&lt;= @enddate
 )
 select * from calendar
 option (maxrecursion 0);

答案1

得分: 0

你可以尝试使用以下代码来填充一个名为"your_table"的新表格中的日期。

你可以将其作为进一步操作的基础。

WITH x AS (SELECT n FROM (VALUES (0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) v(n))
    
select 
convert(date, dat ) Dat
into your_table
from 
(
    SELECT top 100 percent
    ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) Line,
    dateadd(day, ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), '2014-01-01') Dat
    FROM x ones, x tens, x hundreds, x thousands
    ORDER BY 1
) basis
where dat <= '2023-12-31'
英文:

you can try this one to fill a new table your_table with the dates.
You can use that as a basis for your further operations.

WITH x AS (SELECT n FROM (VALUES (0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) v(n))

select 
convert(date, dat ) Dat
into your_table
from 
(
	SELECT top 100 percent
	ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) Line,
	dateadd(day, ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), &#39;2014-01-01&#39;) Dat
	FROM x ones, x tens, x hundreds, x thousands
	ORDER BY 1
) basis
where dat &lt;= &#39;2023-12-31&#39;

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  • 本文由 发表于 2023年2月7日 02:34:28
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