问题

I have translated the code section you provided. Here's the translated code:

我正在进行极小化极大算法的项目，我正在尝试找到一种方法来将棋盘值保存在文本文件中，以便在每次测试程序时不必一遍又一遍地进行计算。我将棋盘存储为嵌套字典。

```python
rows = {
    4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}

我尝试了以下方法，它可以得到期望的结果，但并不是最优化的方法，我相信有更好的方法来做这个。

rows = {
    4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
    1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}

e = []
for key in rows:
    e.append(list(rows[key].values()))
e = str(e)
e = e.replace("[", "")
e = e.replace("]", "")
e = e.replace(" ", "")
e = e.replace(",", "")
print(e)

Please note that the translated code remains the same, and I've retained the code formatting and comments from the original code.

<details>
<summary>英文:</summary>

I&#39;m working on a minimax algorithm project and I am trying to find a way to save board values in a text file so they don&#39;t need to be calculated over and over again each time the program is tested. I have the board stored as a nested dictionary.

rows = {
4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}

I tried doing this, which gives the desired result but is not at all optimized and I'm sure there is a way to do this better.

rows = {
4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}

e = []
for key in rows:
e.append(list(rows[key].values()))
e=str(e)
e=e.replace ("[",""); e=e.replace ("]","")
e=e.replace (" ","")
e=e.replace (",","")
print(e)

</details>


# 答案1
**得分**: 1

你可以使用[`str.join()`][1]，`map`用于将整数转换为字符串：

```python
res = ''.join(''.join(map(str, r.values())) for r in rows.values())
print(res)

输出结果：

00000000000000000000000000000000

res = ''.join(''.join(map(str, r.values())) for r in rows.values())
print(res)

00000000000000000000000000000000