英文:
Converting nested dict into a single unchanging unique number
问题
I have translated the code section you provided. Here's the translated code:
我正在进行极小化极大算法的项目，我正在尝试找到一种方法来将棋盘值保存在文本文件中，以便在每次测试程序时不必一遍又一遍地进行计算。我将棋盘存储为嵌套字典。```pythonrows = {4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},}
我尝试了以下方法，它可以得到期望的结果，但并不是最优化的方法，我相信有更好的方法来做这个。
rows = {4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},}e = []for key in rows:e.append(list(rows[key].values()))e = str(e)e = e.replace("[", "")e = e.replace("]", "")e = e.replace(" ", "")e = e.replace(",", "")print(e)
Please note that the translated code remains the same, and I've retained the code formatting and comments from the original code.<details><summary>英文:</summary>I'm working on a minimax algorithm project and I am trying to find a way to save board values in a text file so they don't need to be calculated over and over again each time the program is tested. I have the board stored as a nested dictionary.
rows = {
4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}
I tried doing this, which gives the desired result but is not at all optimized and I'm sure there is a way to do this better.
rows = {
4:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
3:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
2:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
1:{1:0,2:0,3:0,4:0,5:0,6:0,7:0,8:0},
}
e = []
for key in rows:
e.append(list(rows[key].values()))
e=str(e)
e=e.replace ("[",""); e=e.replace ("]","")
e=e.replace (" ","")
e=e.replace (",","")
print(e)
</details># 答案1**得分**: 1你可以使用[`str.join()`][1]，`map`用于将整数转换为字符串：```pythonres = ''.join(''.join(map(str, r.values())) for r in rows.values())print(res)
输出结果：
00000000000000000000000000000000
英文:
You could make use of a str.join(), map is used to convert integers to strings:
res = ''.join(''.join(map(str, r.values())) for r in rows.values())print(res)
Out:
00000000000000000000000000000000
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