英文:
Subtracting asctime from time module to get hours minutes and seconds in python
问题
You can subtract start from end to calculate the time difference in Python. Here's the code with the print statement converted as you requested:
import time
start = time.asctime(time.localtime(time.time()))
# < some code here >
end = time.asctime(time.localtime(time.time()))
time_format = "%a %b %d %H:%M:%S %Y"
start_time = time.mktime(time.strptime(start, time_format))
end_time = time.mktime(time.strptime(end, time_format))
time_difference = end_time - start_time
hours, remainder = divmod(time_difference, 3600)
minutes, seconds = divmod(remainder, 60)
print(f"{hours} hours, {minutes} minutes, {seconds} seconds")
This code will calculate and print the time difference in hours, minutes, and seconds between end and start.
英文:
How can I subtract end - start to get hours minutes and seconds of time completion in Python?
I have some pseudocode here, I want to convert the print statement to what I said above.
start = time.asctime(time.localtime(time.time()))
< some code here>
end = time.asctime(time.localtime(time.time()))
print(end - start)
答案1
得分: 1
您可以使用Python中的datetime模块来减去两个datetime对象，从而获得一个表示两个时间之间持续时间的timedelta对象。timedelta对象可以通过访问其属性total_seconds()、seconds、minutes、hours和days来进一步提取小时、分钟和秒。以下是一个示例：
import datetime
start = datetime.datetime.now()
end = datetime.datetime.now()
duration = end - start
hours, remainder = divmod(duration.total_seconds(), 3600)
minutes, seconds = divmod(remainder, 60)
英文:
a solution using datetime
You can use the datetime module in Python to subtract two datetime objects and obtain a timedelta object that represents the duration between the two times. The timedelta object can be further used to extract hours, minutes, and seconds by accessing its attributes total_seconds(), seconds, minutes, hours, and days. Here is an example:
import datetime
start = datetime.datetime.now()
end = datetime.datetime.now()
duration = end - start
hours, remainder = divmod(duration.total_seconds(), 3600)
minutes, seconds = divmod(remainder, 60)
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