参数值未在类构造函数中分配

huangapple
go评论98阅读模式
英文:

Parameter values are not getting assigned in class constructor

问题

[System.Serializable]
public class StallData
{
public StallData(ulong stallID, StallSurfaceTextureData stallSurfaceTextureData)
{
StallID = stallID;
StallSurfaceTextureData = stallSurfaceTextureData;
}

  1. [field: SerializeField]
  2. public ulong StallID { get; private set; }
  4. [field: SerializeField]
  5. public StallSurfaceTextureData StallSurfaceTextureData { get; private set; }

}

[System.Serializable]
public class StallSurfaceTextureData
{
public StallSurfaceTextureData(int floorTextureID, int leftTextureID, int rightTextureID, int backWallTextureID)
{
Debug.LogFormat($"f {floorTextureID} l {leftTextureID} r {rightTextureID} b {backWallTextureID}");

  1.     BackWallTextureID = backWallTextureID;
  2.     LeftWallTextureID = leftTextureID;
  3.     RightWallTextureID = rightTextureID;
  4.     FloorTextureID = floorTextureID;
  5. }
  7. [field: SerializeField]
  8. public int BackWallTextureID { get; private set; }
  10. [field: SerializeField]
  11. public int LeftWallTextureID { get; private set; }
  13. [field: SerializeField]
  14. public int RightWallTextureID { get; private set; }
  16. [field: SerializeField]
  17. public int FloorTextureID { get; private set; }

}

英文:

My Class

  1.    [System.Serializable]
  2.    public class StallData
  3.    {
  4.     public StallData(ulong stallID, stallSurfaceTextureData)
  5.     {
  6.       StallID = stallID;
  7.       StallSurfaceTextureData = stallSurfaceTextureData;
  8.     }
  9.     
  10.     [field: SerializeField]
  11.     public ulong StallID{ get; private set; }
  13.     [field: SerializeField]
  14.     public StallSurfaceTextureData StallSurfaceTextureData { get; private set; }
  15. }
  18. [System.Serializable]
  19. public class StallSurfaceTextureData
  20. {
  21.     public StallSurfaceTextureData( int floorTextureID, int leftTextureID, int right, int back)
  22.     {
  23.         Debug.LogFormat($" f {floorTextureID} l {leftTextureID} r {right} b {back}");
  25.         BackWallTextureID = back;
  26.         LeftWallTextureID = leftTextureID;
  27.         RightWallTextureID = right;
  28.         FloorTextureID = floorTextureID;
  29.     }
  30.     
  31.     [field: SerializeField]
  32.     public int BackWallTextureID { get; private set; }
  33.     
  34.     [field: SerializeField]
  35.     public int LeftWallTextureID { get; private set; }
  36.     
  37.     [field: SerializeField]
  38.     public int RightWallTextureID { get;private  set; }
  39.     
  40.     [field: SerializeField]
  41.     public int FloorTextureID { get; private set; }
  42. }

using newtonsoft-json when I am converting my JSON to this class I am getting back, left & right value 0 and for floor, I am getting the correct value.

I am unable to find the reason for it.

Unity version 2021.3.12f1

this is my JSON

  1. {
  2.   "StallID": 889448,
  3.   "StallSurfaceTextureData": 
  4.   {
  5.     "BackWallWallTextureID": 0,
  6.     "LeftWallWallTextureID": 1,
  7.     "RightWallWallTextureID": 2,
  8.     "FloorTextureID": 3
  9.   }
  10. }

I renamed the parameter name, and one time it worked then again I am getting the same issue.

Edit:
I have changed the parameter name in JSon but still the issue persists. The only way it is working is if I am keeping the parameter name and the variable name inside the class is same. I am not getting how the Parameter name is affecting the value assignment in the class?
for ex:
If I keep my class like this it will work

  1.     [System.Serializable]
  2.      public class StallSurfaceTextureData
  3.      {
  4.     public StallSurfaceTextureData( int floorTextureID, int leftWallTextureID, int rightWallTextureID, int backWallTextureID)
  5.     {
  6.         Debug.LogFormat($" f {floorTextureID} l {leftWallTextureID} r {rightWallTextureID} b {backWallTextureID}".ToGreen());
  8.         BackWallTextureID = backWallTextureID;
  9.         LeftWallTextureID = leftWallTextureID;
  10.         RightWallTextureID = rightWallTextureID;
  11.         FloorTextureID = floorTextureID;
  12.     }
  13.     
  14.     [field: SerializeField]
  15.     public int BackWallTextureID { get; private set; }
  16.     
  17.     [field: SerializeField]
  18.     public int LeftWallTextureID { get; private set; }
  19.     
  20.     [field: SerializeField]
  21.     public int RightWallTextureID { get;private  set; }
  22.     
  23.     [field: SerializeField]
  24.     public int FloorTextureID { get; private set; }
  25. }

答案1

得分: 1

Unity需要在JSON和类中的变量名称完全相同。
在JSON中你有BackWallTextureID，而在类中你有BackWallTextureId。

英文:

Unity need to have the same to the letter variables name in JSON and class.
You have BackWallTextureID in JSON and BackWallTextureId in class.

答案2

得分: 0

我尝试了JsonConvert.DeserializeObject(json) - 没有任何问题，我猜这是因为它忽略了构造函数的输入参数，因为对于Newtonsoft.Json来说，它们不存在。如果你想要使用构造函数，输入参数应该与json相同（默认情况下不区分大小写）。

英文:

I tried JsonConvert.DeserializeObject(json) - no any problem, I guess because you constructor input parameters are ignored since they are not exist for Newtonsoft.Json. If you want to use a constructor, input parameters should be the same as json ( case insensitive by default).

huangapple
  • 本文由 发表于 2023年2月6日 17:02:45
  • 转载请务必保留本文链接：https://go.coder-hub.com/75359228.html
  • c#
  • json.net
  • unity-game-engine
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定