英文:
Write a program to replace all even numbers in an array with $ and print the array
问题
这是我的代码。但它不起作用。
#include <stdio.h>#include <stdlib.h>int main(void) {int size, i;setbuf(stdout, NULL);printf("输入数组大小：");scanf("%d", &size);printf("输入数值：");int arr[size];for (i = 0; i < size; i++) {scanf("%d", &arr[i]);if (arr[i] % 2 == 0) {arr[i] = '$';}}for (i = 0; i < size; i++) {printf("%d\n", arr[i]);}return 0;}
结果是：
363361
英文:
This is my code. And it doesn't work.
#include <stdio.h>#include <stdlib.h>int main(void) {int size, i;setbuf(stdout,NULL);printf("Enter array limit: ");scanf("%d",&size);printf("Enter values: ");int arr[size];for(i=0;i<size;i++){scanf("%d",&arr[i]);if(arr[i]%2==0){arr[i]='$';}}for(i=0;i<size;i++){printf("%d\n",arr[i]);}return 0;}
The result is:
363361
答案1
得分: 0
你正在用美元符号的ASCII码替换数字。你可以选择以下两种方法之一：
-
保持数组不变，添加一个if语句，在打印时进行判断。如果是偶数，打印数字，否则打印美元符号($)。
-
创建一个char*数组。为数组的每个元素分配20个字符的空间。使用sprintf在每个元素中打印数字或美元符号($)，然后循环打印新数组的每个元素。
无论哪种方法，都不能将'$'存储在int数组中，然后确定它是一个字符。它只是一个数字。
英文:
You are replacing the number with the ascii code of the dollar character. You can do one of two things:
Leave the array alone and add an if statement where you print. If even, print the number, else print $
Create an array of char*. Allocate 20 chars for each element if the array. Use sprintf to print the number or $ in each element. Loop and print each element of the new array.
Anycase, you can't store '$' in the int array and then determine that It's a character. It is just a number.
答案2
得分: 0
仅翻译代码部分，如下所示：
Just in this for loopfor(i=0;i<size;i++){printf("%d\n",arr[i]);}output elements storing the character constant `'$'` using the conversion specifier `%c`. For examplefor ( i = 0; i < size; i++ ) {printf( arr[i] == '$' ? "%c\n" : "%d\n", arr[i]);}Here is a demonstration program.#include <stdio.h>int main( void ){enum { N = 10 };int arr[N] = { '$', 1, '$', 3, '$', 5, '$', 7, '$', 9 };for (int i = 0; i < N; i++){printf( arr[i] == '$' ? "%c\n" : "%d\n", arr[i] );}}The program output is1$3$5$7$9Or to output elements of the array in a line like$ 1 $ 3 $ 5 $ 7 $ 9you can use the following for loopfor (int i = 0; i < N; i++){printf( arr[i] == '$' ? "%c " : "%d ", arr[i] );}putchar( '\n' );
希望这对你有所帮助。
英文:
Just in this for loop
for(i=0;i<size;i++){printf("%d\n",arr[i]);}
output elements storing the character constant '$' using the conversion specifier %c. For example
for ( i = 0; i < size; i++ ) {printf( arr[i] == '$' ? "%c\n", "%d\n", arr[i]);}
Here is a demonstration program.
#include <stdio.h>int main( void ){enum { N = 10 };int arr[N] = { '$', 1, '$', 3, '$', 5, '$', 7, '$', 9 };for (int i = 0; i < N; i++){printf( arr[i] == '$' ? "%c\n" : "%d\n", arr[i] );}}
The program output is
1$3$5$7$9
Or to output elements of the array in a line like
$ 1 $ 3 $ 5 $ 7 $ 9
you can use the following for loop
for (int i = 0; i < N; i++){printf( arr[i] == '$' ? "%c " : "%d ", arr[i] );}putchar( '\n' );
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