英文:
Reading specific number of lines
问题
要在C中读取特定行数的内容应该如何做？有什么提示，因为我似乎找不到相关的线程。
我想要从文件中读取N行，N是由用户提供的参数。
直到这一点，我一直是这样读取文件的：（逐行直到NULL）
int main(void) {
char line[50];
FILE *file;
file = fopen("filename.txt", "r");
printf("文件包含：\n");
while (fgets(line, 50, file) != NULL) {
printf("%s", line);
}
fclose(file);
return(0);
}
英文:
How should I read a specific number of lines in C? Any tips, since I can't seem to find a relevant thread.
I would like to read N lines from a file and N would be argument given by the user.
Up until this point I have been reading files this way: (line by line until NULL)
int main(void) {
char line[50];
FILE *file;
file= fopen("filename.txt", "r");
printf("File includes:\n");
while (fgets(line, 50, file) != NULL) {
printf("%s", line);
}
fclose(file);
return(0);
}
答案1
得分: 3
如果用户提供了N，您可以使循环计数达到N：
for (int i = 0; i < N && fgets(line, sizeof line, file); ++i) {
fputs(line, stdout);
}
英文:
If N is given by the user, you could just make your loop count up to N:
for (int i = 0; i < N && fgets(line, sizeof line, file); ++i) {
fputs(line, stdout);
}
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