英文:
I'd like to match the digit of IP with C
问题
根据协议，我必须发送客户端的IP地址，但我不知道如何做。
我正在使用C语言制作Socket TCP通信服务器，根据协议。
一旦客户端访问，数据必须发送到该IP地址。
协议包括：SendIP(16字节) DestinationIP(16字节) ...
IP地址的数字必须匹配，如000.000.000.000-（例如127.000.000.001）。
请给我一些提示！
我将接收到的IP地址放在结构体中，并提取了点号的数字。如果减去的值不是4，我逐个移动了数字。
struct UserData {
char Ip_Address[16];
char port[10];
char strConnTime[30];
char strCloseTime[30];
};
UserData m_user_list[10];
while (1) {
dlg->accept_sock = accept(dlg->server_sock, (SOCKADDR*)&dlg->accept_addr, &size);
if (dlg->accept_sock == SOCKET_ERROR) {
break;
}
strcpy(m_user_list[index].Ip_Address, inet_ntoa(dlg->accept_addr.sin_addr));
int count = 0;
int dotcount[3];
for (int i = 0; i <= 16; i++) {
if (m_user_list[index].Ip_Address[i] == '.') {
dotcount[count++] = i;
}
}
if (dotcount[0] - dotcount[1] != 4) {
for (int j = 0; j <= 16; j++) {
m_user_list[index].Ip_Address[j + 1] = m_user_list[index].Ip_Address[j];
}
}
}
希望这些提示对你有所帮助！
英文:
I have to send the client's IP according to the protocol, but I don't know how.
I am making Socket TCP communication server in C according to the protocol.
As soon as the client accesses, the data must be sent to that IP.
The protocol includes: SendIP(16BYTE) DestinationIP(16BYTE) ...
IP digits must match like 000.000.000.000- (ex. 127.000.000.001)
Please give me some hint!
I put the IP I received in the structure and received the digits of . If the subtracted value was not 4, I shifted the digits one by one.
struct UserData {
char Ip_Address[16];
char port[10];
char strConnTime[30];
char strCloseTime[30];
};
UserData m_user_list[10];
while(1)
{
dlg->accept_sock = accept(dlg->server_sock, (SOCKADDR*)&dlg->accept_addr, &size);
if (dlg->accept_sock == SOCKET_ERROR)
{
break;
}
strcpy(m_user_list[index].Ip_Address, inet_ntoa(dlg->accept_addr.sin_addr));
int count = 0;
int dotcount[3];
for (int i = 0; i <= 16; i++)
{
if (m_user_list[index].Ip_Address[i] == '.')
{
dotcount[count++] = i;
}
}
if (dotcount[0] - dotcount[1] != 4)
{
for (int j = 0; j <= 16; j++)
{
m_user_list[index].Ip_Address[j + 1] = m_user_list[index].Ip_Address[j];
}
}
}
答案1
得分: 0
这是您提供的代码部分的翻译：
while (1)
{
#if 1
dlg->accept_addr = { 0 };
dlg->accept_addr.sin_family = AF_INET;
dlg->accept_addr.sin_port = htons(30110);
dlg->accept_addr.sin_addr.s_addr = htonl(INADDR_ANY);
int size = sizeof(SOCKADDR_IN);
#endif
dlg->accept_sock = accept(dlg->server_sock, (SOCKADDR*)&dlg->accept_addr, &size);
if (dlg->accept_sock == SOCKET_ERROR)
{
break;
}
strcpy(m_user_list[index].Ip_Address, inet_ntoa(dlg->accept_addr.sin_addr));
int count = 0;
char *digitIp[4] = { NULL, };
char* pIpAddr = strtok(m_user_list[index].Ip_Address, ".");
char copyIP[16] = { NULL, };
while (pIpAddr != NULL)
{
digitIp[count] = pIpAddr;
count++;
pIpAddr = strtok(NULL, ".");
}
count = 0;
sprintf(copyIP, "%03s.%03s.%03s.%03s-", digitIp[0], digitIp[1], digitIp[2], digitIp[3]);
accept_list.push_back(dlg->accept_sock);
strcpy(m_user_list[index].Ip_Address, copyIP);
}
希望这对您有所帮助。如果您需要进一步的翻译或有其他问题，请随时提出。
英文:
I use the strtok
while (1)
{
#if 1
dlg->accept_addr = { 0 };
dlg->accept_addr.sin_family = AF_INET;
dlg->accept_addr.sin_port = htons(30110);
dlg->accept_addr.sin_addr.s_addr = htonl(INADDR_ANY);
int size = sizeof(SOCKADDR_IN);
#endif
dlg->accept_sock = accept(dlg->server_sock, (SOCKADDR*)&dlg->accept_addr, &size);
if (dlg->accept_sock == SOCKET_ERROR)
{
break;
}
strcpy(m_user_list[index].Ip_Address, inet_ntoa(dlg->accept_addr.sin_addr));
int count = 0;
char *digitIp[4] = { NULL, };
char* pIpAddr = strtok(m_user_list[index].Ip_Address, ".");
char copyIP[16] = { NULL, };
while (pIpAddr != NULL)
{
digitIp[count] = pIpAddr;
count++;
pIpAddr = strtok(NULL, ".");
}
count = 0;
sprintf(copyIP, "%03s.%03s.%03s.%03s-", digitIp[0], digitIp[1], digitIp[2], digitIp[3]);
accept_list.push_back(dlg->accept_sock);
strcpy(m_user_list[index].Ip_Address, copyIP);
}
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