“FATAL ERROR: SIGABRT” 在自定义字符串类中定义字符串构造函数时发生。

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英文:

"FATAL ERROR: SIGABRT" when defining a string constructor in a custom String class

问题

这个错误发生了

  1. 致命错误：测试用例崩溃：SIGABRT - 中止（异常终止）信号
  2. ::error::错误：以代码 134 和信号 null 退出

当我在测试一个字符串构造函数 "String::String(const char* other)" 时发生的。

  1. String::String(const char* other) // 我说的构造函数
  2. {
  3.      if (other == nullptr)
  4.      {
  5.           String();
  6.      }
  7.      else if (other != nullptr)
  8.      {
  9.           int count{0};
  10.           for (int i = 0; other[i] != '
    String::String(const char* other) // 我说的构造函数
  11. {
  12.      if (other == nullptr)
  13.      {
  14.           String();
  15.      }
  16.      else if (other != nullptr)
  17.      {
  18.           int count{0};
  19.           for (int i = 0; other[i] != '\0'; ++i)
  20.           {
  21.               count = count + 1;
  22.           }
  23.           slength = count;
  24.           // 删除 [] ifmt; // ?
  25.           ifmt = new char [slength + 1];
  26.           for (int i = 0; i < slength; ++i)    
  27.           {
  28.               ifmt[i] = other[i];
  29.           }
  30.           ifmt[slength] = '\0'; 
  31.      }
  32. }
  34. String::String()
  35. {
  36.     slength = 0; 
  37.     ifmt = new char[slength + 1]; 
  38.     ifmt[0] = '\0';
  39. }
  40. '; ++i)
  41.           {
  42.               count = count + 1;
  43.           }
  44.           slength = count;
  45.           // 删除 [] ifmt; // ?
  46.           ifmt = new char [slength + 1];
  47.           for (int i = 0; i < slength; ++i)    
  48.           {
  49.               ifmt[i] = other[i];
  50.           }
  51.           ifmt[slength] = '
    String::String(const char* other) // 我说的构造函数
  52. {
  53.      if (other == nullptr)
  54.      {
  55.           String();
  56.      }
  57.      else if (other != nullptr)
  58.      {
  59.           int count{0};
  60.           for (int i = 0; other[i] != '\0'; ++i)
  61.           {
  62.               count = count + 1;
  63.           }
  64.           slength = count;
  65.           // 删除 [] ifmt; // ?
  66.           ifmt = new char [slength + 1];
  67.           for (int i = 0; i < slength; ++i)    
  68.           {
  69.               ifmt[i] = other[i];
  70.           }
  71.           ifmt[slength] = '\0'; 
  72.      }
  73. }
  75. String::String()
  76. {
  77.     slength = 0; 
  78.     ifmt = new char[slength + 1]; 
  79.     ifmt[0] = '\0';
  80. }
  81. '; 
  82.      }
  83. }
  85. String::String()
  86. {
  87.     slength = 0; 
  88.     ifmt = new char[slength + 1]; 
  89.     ifmt[0] = '
    String::String(const char* other) // 我说的构造函数
  90. {
  91.      if (other == nullptr)
  92.      {
  93.           String();
  94.      }
  95.      else if (other != nullptr)
  96.      {
  97.           int count{0};
  98.           for (int i = 0; other[i] != '\0'; ++i)
  99.           {
  100.               count = count + 1;
  101.           }
  102.           slength = count;
  103.           // 删除 [] ifmt; // ?
  104.           ifmt = new char [slength + 1];
  105.           for (int i = 0; i < slength; ++i)    
  106.           {
  107.               ifmt[i] = other[i];
  108.           }
  109.           ifmt[slength] = '\0'; 
  110.      }
  111. }
  113. String::String()
  114. {
  115.     slength = 0; 
  116.     ifmt = new char[slength + 1]; 
  117.     ifmt[0] = '\0';
  118. }
  119. ';
  120. }

在我的自定义 String 类中。

  1. private:
  2.         
  3.     int slength;
  4.     char* ifmt;

我收到的建议之一是创建一个新的选项分支来处理 "负长度" 并在这种情况下构造一个空字符串，但我不知道什么是 "负长度"。

我还在互联网上搜索了一些案例，但我发现我已经按照他们建议的方式做了，但仍然不起作用。
https://www.geeksforgeeks.org/how-to-create-a-custom-string-class-in-c-with-basic-functionalities/
https://stackoverflow.com/questions/22027697/design-a-string-class-constructor-c
https://stackoverflow.com/questions/4719908/custom-string-exercise-in-c

如果有人能在这种情况下提供一些指导，我将不胜感激。

英文:

This error occurred

  1. FATAL ERROR: test case CRASHED: SIGABRT - Abort (abnormal termination) signal
  2. ::error::Error: Exit with code: 134 and signal: null

when I was testing a string constructor "String::String(const char* other)"

  1. String::String(const char* other) // the constructor I&#39;m talking about
  2.     {
  3.          if (other == nullptr)
  4.          {
  5.               String();
  6.          }
  7.          else if (other != nullptr)
  8.          {
  9.               int count{0};
  10.               for (int i = 0; other[i] != &#39;
    String::String(const char* other) // the constructor I&#39;m talking about
  11. {
  12. if (other == nullptr)
  13. {
  14. String();
  15. }
  16. else if (other != nullptr)
  17. {
  18. int count{0};
  19. for (int i = 0; other[i] != &#39;\0&#39;; ++i)
  20. {
  21. count = count + 1;
  22. }
  23. slength = count;
  24. // delete [] ifmt; // ?
  25. ifmt = new char [slength + 1];
  26. for (int i = 0; i &lt; slength; ++i)    
  27. {
  28. ifmt[i] = other[i];
  29. }
  30. ifmt[slength] = &#39;\0&#39;; 
  31. }
  32. }
  33. }
  34. String::String()
  35. {
  36. slength = 0; 
  37. ifmt = new char[slength + 1]; 
  38. ifmt[0] = &#39;\0&#39;;
  39. }
  40. &#39;; ++i)
  41.               {
  42.                   count = count + 1;
  43.               }
  44.               slength = count;
  45.               // delete [] ifmt; // ?
  46.               ifmt = new char [slength + 1];
  47.               for (int i = 0; i &lt; slength; ++i)    
  48.               {
  49.                   ifmt[i] = other[i];
  50.               }
  51.               ifmt[slength] = &#39;
    String::String(const char* other) // the constructor I&#39;m talking about
  52. {
  53. if (other == nullptr)
  54. {
  55. String();
  56. }
  57. else if (other != nullptr)
  58. {
  59. int count{0};
  60. for (int i = 0; other[i] != &#39;\0&#39;; ++i)
  61. {
  62. count = count + 1;
  63. }
  64. slength = count;
  65. // delete [] ifmt; // ?
  66. ifmt = new char [slength + 1];
  67. for (int i = 0; i &lt; slength; ++i)    
  68. {
  69. ifmt[i] = other[i];
  70. }
  71. ifmt[slength] = &#39;\0&#39;; 
  72. }
  73. }
  74. }
  75. String::String()
  76. {
  77. slength = 0; 
  78. ifmt = new char[slength + 1]; 
  79. ifmt[0] = &#39;\0&#39;;
  80. }
  81. &#39;; 
  82.          }
  83. 	}
  84.     }
  85. String::String()
  86. 	{
  87. 		slength = 0; 
  88. 		ifmt = new char[slength + 1]; 
  89. 		ifmt[0] = &#39;
    String::String(const char* other) // the constructor I&#39;m talking about
  90. {
  91. if (other == nullptr)
  92. {
  93. String();
  94. }
  95. else if (other != nullptr)
  96. {
  97. int count{0};
  98. for (int i = 0; other[i] != &#39;\0&#39;; ++i)
  99. {
  100. count = count + 1;
  101. }
  102. slength = count;
  103. // delete [] ifmt; // ?
  104. ifmt = new char [slength + 1];
  105. for (int i = 0; i &lt; slength; ++i)    
  106. {
  107. ifmt[i] = other[i];
  108. }
  109. ifmt[slength] = &#39;\0&#39;; 
  110. }
  111. }
  112. }
  113. String::String()
  114. {
  115. slength = 0; 
  116. ifmt = new char[slength + 1]; 
  117. ifmt[0] = &#39;\0&#39;;
  118. }
  119. &#39;;
  120. 	}

in my custom String class.

  1. private:
  2.             
  3. 		int slength;
  4. 		char* ifmt;

One of the suggestions I received was to create a new option branch to handle "negative length" and construct an empty string in this case, but I have no idea what "negative length" is.

I have also searched for some case on the Internet but I found I have done the things they suggested but it still doesn't work.
https://www.geeksforgeeks.org/how-to-create-a-custom-string-class-in-c-with-basic-functionalities/
https://stackoverflow.com/questions/22027697/design-a-string-class-constructor-c
https://stackoverflow.com/questions/4719908/custom-string-exercise-in-c

I will be thankful if anyone could give some guidance in this case.

答案1

得分: 0

这段代码片段中的部分翻译如下：

如果 other 为 nullptr，则以下代码段：

  1. if (other == nullptr)
  2. {
  3.      String();
  4. }

是没有意义的。

在这个语句中：

  1. String();

会创建一个临时对象，该对象会立即被销毁。

因此，当传递一个空指针时，类的对象会具有未初始化的数据成员。

请注意，这里存在一个多余的右括号：

  1. //...
  2. }
  3. }
  4. String::String()
英文:

This code snippet

  1.      if (other == nullptr)
  2.      {
  3.           String();
  4.      }

does not make sense.

In this statement

  1.   String();

there is created a temporary object that at once is destroyed.

As a result when a null pointer is passed then the object of the class has uninitialized data members.

Pay attention to that there is a redundant closing brace

  1.     //...
  2. }
  3. }

String::String()

huangapple
  • 本文由 发表于 2023年2月6日 04:05:41
  • 转载请务必保留本文链接：https://go.coder-hub.com/75355167.html
  • c++
  • class
  • constructor
  • scope
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