Laravel 迁移更改外键为 nullOnDelete() 并设置 nullable(true)。

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英文:

Laravel migrations change foreign key to be nullOnDelete() and nullable(true)

问题

我有这个迁移,第一次创建了一个外键:

Schema::table('user_plays_quizzes', function (Blueprint $table) {
    $table->bigInteger('quiz_id')->unsigned()->change();
    $table->foreign('quiz_id')->references('id')->on('quizzes');
});

现在我有一个新的迁移,我想将这个外键更新为nullable(true),并且设置为nullOnDelete()

我尝试了很多次,但总是出现错误,我觉得这是最接近的尝试:

Schema::table('user_plays_quizzes', function (Blueprint $table) {
    $table->bigInteger('quiz_id')->unsigned()->nullable(true)->change();
    $table->foreign('quiz_id')->references('id')->on('quizzes')->nullOnDelete();
});

可惜它也不起作用:

SQLSTATE[HY000]: General error: 1005 无法创建表d039e62e.user_plays_quizzes (错误: 121 "写入或更新时的重复键") (SQL: 修改表user_plays_quizzes,添加外键约束user_plays_quizzes_quiz_id_foreign(quiz_id)参考quizzes(id),删除时设置为null)

不知道如何解决它。我甚至无法删除键并重新创建它们。也许有人有办法如何使用迁移来更新它。

英文:

I have this migration where I created a foreign key the first time:

Schema::table('user_plays_quizzes', function (Blueprint $table) {
    $table->bigInteger('quiz_id')->unsigned()->change();
    $table->foreign('quiz_id')->references('id')->on('quizzes');
});

Now I have a new migration, where I want to update this foreign key to be nullable(true) and to be nullOnDelete().

I tried it so many times, but there are always errors, I feel like this is the closest approach:

Schema::table('user_plays_quizzes', function (Blueprint $table) {
    $table->bigInteger('quiz_id')->unsigned()->nullable(true)->change();
    $table->foreign('quiz_id')->references('id')->on('quizzes')->nullOnDelete();
});

Sadly it also does not work:

> SQLSTATE[HY000]: General error: 1005 Can't create table d039e62e.user_plays_quizzes (errno: 121
"Duplicate key on write or update") (SQL: alter table user_plays_quizzes add constraint user_plays_quizzes_quiz_id_foreign for
eign key (quiz_id) references quizzes (id) on delete set null)

No Idea how to solve it. I cant even drop the keys and recreate them aswell. Maybe someone has an idea how I can update it with a migration

答案1

得分: 1

为什么不能删除密钥并重新创建它?

public function up()
{
    Schema::table('user_plays_quizzes', function (Blueprint $table) {
        // 删除quiz_id列上的外键约束
        $table->dropForeign(['quiz_id']);
        // 修改quiz_id列
        $table->bigInteger('quiz_id')->unsigned()->nullable(true)->change();
        // 在quiz_id列上添加新的外键约束
        $table->foreign('quiz_id')->references('id')->on('quizzes')->nullOnDelete();
    });
}

public function down()
{
    Schema::table('user_plays_quizzes', function (Blueprint $table) {
        // 删除quiz_id列上的外键约束
        $table->dropForeign(['quiz_id']);
        // 将quiz_id列还原到之前的状态
        $table->bigInteger('quiz_id')->unsigned()->nullable(false)->change();
        // 还原quiz_id列上的原始外键约束
        $table->foreign('quiz_id')->references('id')->on('quizzes');
    });
}
英文:

Why can't you drop the key and recreate it?

public function up()
{
    Schema::table('user_plays_quizzes', function (Blueprint $table) {
        // Drop fk constraint on quiz_id column
        $table->dropForeign(['quiz_id']);
        // Alter quiz_id column
        $table->bigInteger('quiz_id')->unsigned()->nullable(true)->change();
        // Add new fk constraint on quiz_id column
        $table->foreign('quiz_id')->references('id')->on('quizzes')->nullOnDelete();

    });
}

public function down()
{
    Schema::table('user_plays_quizzes', function (Blueprint $table) {
        // Drop fk constraint on quiz_id column
        $table->dropForeign(['quiz_id']);
        // Restore quiz_id column to how it was before
        $table->bigInteger('quiz_id')->unsigned()->nullable(false)->change();
        // Restore original fk constraint on quiz_id column
        $table->foreign('quiz_id')->references('id')->on('quizzes');
    });
}

huangapple
  • 本文由 发表于 2023年2月6日 03:21:52
  • 转载请务必保留本文链接:https://go.coder-hub.com/75354900.html
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