英文:
What is the issue on my recursive function made in go?
问题
我正在学习使用《Go语言圣经》这本书学习Golang，在第5章第5.3节（多返回值）的练习5.5中，我需要实现一个名为countWordAndImages的函数，该函数接收来自golang.org/x/net包的html Node，并计算html文件中的单词和图片数量。我实现了以下函数，但是无论出于什么原因，我都会收到每个words和images返回变量的0值。
func countWordsAndImages(n *html.Node) (words, images int) {
if n.Type == html.TextNode {
words += wordCount(n.Data)
} else if n.Type == html.ElementNode && n.Data == "img" { // if tag is img on element node
images++
}
for c := n.FirstChild; c != nil; c = n.NextSibling {
tmp_words, tmp_images := countWordsAndImages(c)
words, images = words+tmp_words, images+tmp_images
}
return words, images
}
func wordCount(s string) int {
n := 0
scan := bufio.NewScanner(strings.NewReader(s))
scan.Split(bufio.ScanWords)
for scan.Scan() {
n++
}
return n
}
我尝试避免在函数中对返回变量进行命名（(int, int)）。
英文:
I am learning Golang with the book "The Go Programming Language", in chapter 5 section 5.3 (Multiple Return Values) exercise 5.5 I have to implement the function countWordAndImages that receives an html Node from the (golang.org/x/net) package, and counts the number of words and images inside an html file, I implemented the following function, but for any reason I receive 0 values for each words and images returned variables.
func countWordsAndImages(n *html.Node) (words, images int) {
if n.Type == html.TextNode {
words += wordCount(n.Data)
} else if n.Type == html.ElementNode && n.Data == "img" { // if tag is img on element node
images++
}
for c := n.FirstChild; c != nil; c = n.NextSibling {
tmp_words, tmp_images := countWordsAndImages(c)
words, images = words+tmp_words, images+tmp_images
}
return words, images
}
func wordCount(s string) int {
n := 0
scan := bufio.NewScanner(strings.NewReader(s))
scan.Split(bufio.ScanWords)
for scan.Scan() {
n++
}
return n
}
I tried to avoid naming the return varibles tuple in the function ((int, int)).
答案1
得分: 3
使用c.NextSibling来前进到下一个兄弟节点，而不是n.NextSibling：
for c := n.FirstChild; c != nil; c = c.NextSibling {
⋮
}
链接：https://go.dev/play/p/cm51yG8Y7Ry
英文:
Use c.NextSibling to advance to the next sibling, not n.NextSibling:
for c := n.FirstChild; c != nil; c = c.NextSibling {
⋮
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