英文:
Comparing ways of opening files in Python
问题
- 什么情况下会更喜欢使用方法2，而不是方法1，尽管后者更模块化？
- 是否存在任何技术上的区别？
- 当需要使用Path对象时，方法2可能优于方法1，即使方法1更模块化。
- 是的，方法1支持字符串和Path对象，而方法2仅支持Path对象。这是它们之间的技术区别之一。
英文:
There are two ways of opening files for high-level I/O in Python.
Method 1: supports both string and Path objects.
# This is analogous to `io.open` in Python 3.
with open(filepath) as f:
...
Method 2: supports only Path objects.
from pathlib import Path
...
# filepath must be a Path object.
with filepath.open() as f:
...
Note: We are not considering os.open here as it is only intended for low-level I/Os.
- When is method 2 ever preferred over method 1 when the latter is more modular?
- Are there any technical differences?
答案1
得分: 0
Method 2在使用Path对象表示的文件路径时更受欢迎，因为它更简洁且易于阅读。这两种方法在技术上没有区别，因为open只是一个接受文件路径并返回文件对象的函数，而Path.open是Path对象的一个方法，执行相同的操作。
如果您使用字符串表示的文件路径，则应使用方法1，因为它更灵活，可以处理字符串和Path对象。但是，如果您专门使用Path对象，那么可以使用方法2以简化和清晰化代码。
英文:
Method 2 is preferred when you are working with file paths represented as Path objects, because it is more concise and easier to read. There are no technical differences between the two methods, as open is simply a function that takes a file path and returns a file object, and Path.open is a method of the Path object that does the same thing.
If you are working with file paths represented as strings, then you should use method 1, as it is more flexible and can handle both string and Path objects. However, if you are working with Path objects exclusively, then you can use method 2 for simplicity and clarity.
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