英文:
Print pandas rows cells as string
问题
我的输出：
0 car
1 bus
2 aircraft
3 rocket
4 subway
5 train
英文:
I'm trying to print a data frame where each cell appears as a string:
Dataset
a b c0 car new york queens1 bus california los angeles2 aircraft illinois chicago3 rocket texas houston4 subway maine augusta5 train florida miami
Mon script:
for index, row in df.iterrows():print(df["a"], "\n", testes["c"], "\n", testes["b"])
My output:
0 car
1 bus
2 aircraft
3 rocket
4 subway
5 train
Name: a, dtype: object
...
Good output:
carqueensnew yorkbuslos angelescalifornia...
答案1
得分: 2
循环较慢，但如果使用row Series，则仍然可以实现：
for index, row in df.iterrows():print(row["a"], row["c"], row["b"], sep="\n")
另一个方法是将列转换为NumPy数组：
for a, b, c in df[['a', 'b', 'c']].to_numpy():print(a, c, b, sep="\n")
或者使用zip：
for a, b, c in zip(df['a'], df['b'], df['c']):print(a, c, b, sep="\n")
英文:
Looping is slow, but possible if use row Series:
for index, row in df.iterrows():print(row["a"], row["c"], row["b"], sep="\n")
Another idea is convert columns to numpy array:
for a, b, c in df[['a','b','c']].to_numpy():print(a, c, b, sep="\n")
Or zip:
for a, b, c in zip(df['a'],df['b'],df['c']):print(a, c, b, sep="\n")
答案2
得分: 2
使用apply方法来实现这一点：
df.apply(lambda row: print(f"{row['a']}\n{row['c']}\n{row['b']}\n"), axis=1)
英文:
One way to achieve that is using apply:
df.apply(lambda row: print(f"{row['a']}\n{row['c']}\n{row['b']}\n"), axis = 1)
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