英文:
Is it possible in base R to replace multiple integers with corresponding strings like a dictionary?
问题
类似于此问题：https://stackoverflow.com/questions/63173687/replace-multiple-values-in-r 但是：我只想使用基本的R，并且我想替换整数，因此下面采用的命名向量解决方案不起作用：
testing <- data.frame(var1 = c(1, 6, 17))# 这是不可能的dict <- c(1 = 'ICMP',6 = 'TCP',17 = 'UDP',)testing$var1 <- dict[testing$var1]
我知道可以这样做
testing$var1[testing$var1 == 1] <- "ICMP"testing$var1[testing$var1 == 6] <- "TCP"testing$var1[testing$var1 == 17] <- "UDP"
但是在基本R中是否有更方便的方法？
英文:
Similar to this question: https://stackoverflow.com/questions/63173687/replace-multiple-values-in-r but: I would like to only use base R and I would like to replace integers, so the named vector solution adopted as below does not work:
testing <- data.frame(var1 = c(1, 6, 17))# this is not possibledict <- c(1 = 'ICMP',6 = 'TCP',17 = 'UDP',)testing$var1 <- dict[testing$var1]
I know I can do
testing$var1[testing$var1 == 1] <- "ICMP"testing$var1[testing$var1 == 6] <- "TCP"testing$var1[testing$var1 == 17] <- "UDP"
but isn't there a more convenient way in base R?
答案1
得分: 2
创建命名向量字典
dict <- c('ICMP', 'TCP', 'UDP')
names(dict) <- c(1, 6, 17)
替换匹配的值
testing$var2 <- dict[as.character(testing$var1)]
var1 var2
1 1 ICMP
2 6 TCP
3 17 UDP
英文:
# create named vector dictdict <- c('ICMP', 'TCP', 'UDP')names(dict) <- c(1,6,17)# replace matching valuestesting$var2 <- dict[as.character(testing$var1)]# var1 var2# 1 1 ICMP# 2 6 TCP# 3 17 UDP
答案2
得分: 2
testing <- data.frame(var1 = c(1, 6, 17))dict <- data.frame(code = c(1, 6, 17), abbr = c('ICMP', 'TCP', 'UDP'))merge(testing, dict, by.x = "var1", by.y = "code")# var1 abbr#1 1 ICMP#2 6 TCP#3 17 UDPtesting$var1 <- merge(testing, dict, by.x = "var1", by.y = "code")$abbr
英文:
testing <- data.frame(var1 = c(1, 6, 17))dict <- data.frame(code = c(1, 6, 17), abbr = c('ICMP', 'TCP', 'UDP'))merge(testing, dict, by.x = "var1", by.y = "code")# var1 abbr#1 1 ICMP#2 6 TCP#3 17 UDPtesting$var1 <- merge(testing, dict, by.x = "var1", by.y = "code")$abbr
答案3
得分: 2
以下是翻译好的部分：
有多种选项。首先，您可以使用字符串作为索引：
dict <- c("1" = "ICMP", "6" = "TCP")dict[as.character(testing$var)]
您也可以通过执行 names(dict) <- c(1, 6) 来实现相同的效果。
然后，您可以使用反向哈希：
dict <- c(ICMP = 1, TCP = 6)names(dict)[match(testing$var1, dict)]
英文:
There is a number of options. First, you can use strings as indices:
dict <- c("1" = "ICMP", "6" = "TCP")dict[ as.character(testing$var) ]
You can achieve the same by doing names(dict) <- c(1, 6).
Then, you can use a reverse hash:
dict <- c(ICMP = 1, TCP = 6)names(dict)[ match(testing$var1, dict) ]
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