英文:
Skipping array items based in a list of intervals
问题
所以我正在尝试使用Python编写一个程序，以自动获取给定音阶中的所有音符。
我想要创建音符列表：
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']
然后按照以下间隔跳过它们的索引：
intervals = [2, 1, 2, 2, 1, 2, 2]
提前谢谢！
我尝试手动完成它，但我真的想要自动化整个过程。
英文:
So I'm trying to code a program for my girlfriend in python to automate the process of getting all musical notes in a given scale.
I want to make the list of notes:
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']
skip their indexes by this set of intervals:
intervals = [2, 1, 2, 2, 1, 2, 2]
Thank you in advance!
I tried to do it manually but I really want to automate all the process.
答案1
得分: 1
你可以使用模运算来实现这个功能
与Edo Akse写的类似 -
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']intervals = [2, 1, 2, 2, 1, 2, 2]idx = 3for interval in intervals:print(notes[idx])idx += intervalidx %= len(notes)
结果
D#FF#G#A#BC#
英文:
You can use modular arithmetic for this
Similar to what Edo Akse wrote -
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']intervals = [2, 1, 2, 2, 1, 2, 2]idx = 3for interval in intervals:print(notes[idx])idx += intervalidx %= len(notes)
result
D#FF#G#A#BC#
答案2
得分: 0
使用一个索引来表示音符，从你想要开始的位置开始，并在循环中将每个间隔添加到索引中。如果超过列表末尾，则减去列表的长度以循环播放音符列表。
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']intervals = [2, 1, 2, 2, 1, 2, 2]idx = 3for interval in intervals:print(notes[idx])idx += intervalif idx > len(notes):idx -= len(notes)
输出
D#FF#G#A#BC#
英文:
use an index for the notes, start where you want, and add each interval to the index in a loop. Subtract length of the list if you're past the end to loop the notes list.
notes = ['C', 'C#', 'D', 'D#', 'E', 'F', 'F#', 'G', 'G#', 'A', 'A#', 'B']intervals = [2, 1, 2, 2, 1, 2, 2]idx = 3for interval in intervals:print(notes[idx])idx += intervalif idx > len(notes):idx -= len(notes)
output
D#FF#G#A#BC#
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