英文:
A Python game in which both a user and a computer randomly chooses a number from 1 - 10 and if the numbers are the same, the user wins else, he loses
问题
import randomclass Game():def __init__(self, computer_choice, user_choice):self.computer_choice = computer_choiceself.user_choice = user_choicedef computer(self):self.computer_choice = random.randint(0, 10)def user(self):self.user_choice = int(input("输入一个从0到10的随机数字："))def decision(self):if self.user_choice >= 0 and self.user_choice <= 10:if self.computer_choice == self.user_choice:print("你赢了！")else:print("你输了！")else:print("你输入了一个无效的选项")def main():game = Game(0, 0)game.computer()game.user()game.decision()if __name__ == "__main__":main()
英文:
Write a game in Python so that a user will randomly choose a number from 0 to 10 and the computer will also do same. If the numbers are equal, you win else you lose.
This is what I wrote. When I run, nothing happens. Can anyone rewrite the full game for me?
import randomclass Game():def __init__(self, computer_choice, user_choice):self.computer_choice = computer_choiceself.user_choice = user_choicedef computer(self):self.computer_choice = random.randint(range(1,10))def user(self):self.user_choice= int(input("Enter a random number from 1 to 10: "))def decision(self):if self.user_choice == int(range(1,10)):if self.computer_choice == self.user_choice:print("You won!")else:print("You lost!")else:print("You entered an invalid option")def main():if __name__ == "__main__":main()</details># 答案1**得分**: 0很难确定，因为我们无法看到`main`中的内容，但问题很可能出在这一行：```pythonif self.user_choice == int(range(1, 10)):
您试图比较用户的选择，一个介于1到10之间的整数，与一系列整数，即一个范围对象。在最佳情况下，这不会起作用。在这种情况下，将范围转换为整数应该会引发TypeError异常。相反，您可以这样写：
if self.user_choice in range(1, 11):
或者更好的写法是：
if 1 <= self.user_choice <= 10:
英文:
It is hard to know for sure since we can't see what is in main, but the problem could very well be this line:
if self.user_choice == int(range(1,10)):
You are attempting to compare the user's choice, an integer between 1 and 10, with a range of integers, a range object. Under the best of circumstances that would not work. In this case, you casting the range to an int should result in a TypeError exception. Instead, you could write:
if self.user_choice in range(1, 11):
or better yet:
if 1 <= self.user_choice <= 10:
答案2
得分: 0
注意：主要问题已在rhurwitz的回答中得到解决，但还有一个补充：
在main函数中，您陷入了一个无限循环：我还建议这样做：
def main():if __name__ == "__main__":game = Game(0, 0)game.computer()game.user()game.decision()
总之：
import randomclass Game():def __init__(self):self.computer_choice = random.randint(1,10)self.user_choice = int(input("输入一个从1到10的随机数字："))def decision(self):if self.user_choice in list(range(11)):if self.computer_choice == self.user_choice:print("你赢了！")else:print("你输了！")else:print("您输入了无效选项")def main():game = Game()game.decision()main()
英文:
Note: Main problem is fixed in rhurwitz's answer, but there is an addition:
You are entering an infinite loop in the main function: I'd also recommend doing:
def main():if __name__ == "__main__":game = Game(0, 0)game.computer()game.user()game.decision()
In all:
import randomclass Game():def __init__(self):self.computer_choice = random.randint(1,10)self.user_choice = int(input("Enter a random number from 1 to 10: "))def decision(self):if self.user_choice in list(range(11)):if self.computer_choice == self.user_choice:print("You won!")else:print("You lost!")else:print("You entered an invalid option")def main():game = Game()game.decision()main()
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