英文:
Search a string using list elements for matches and return the match found
问题
我试图在字符串中查找列表中的任何元素，并返回找到的匹配项。
我目前有以下代码：
y = "test string"z = ["test", "banana", "example"]if any(x in y for x in z):match_found = xprint("Match: " + match_found)
显然，这不起作用，但是否有一种好的方法来实现这个，除了使用for循环和if循环？
英文:
I am trying to search a string for any elements in a list, and return the match found.
I currently have
y = "test string"z = ["test", "banana", "example"]if any(x in y for x in z):match_found = xprint("Match: " + match_found)
This obviously does not work, but is there a good way to accomplish this besides using a for loop and an if loop?
答案1
得分: 0
以下是翻译好的部分：
我认为你正在寻找这个text = "测试字符串"words = ["测试", "香蕉", "示例"]found_words = [word for word in words if word in text]print(found_words)结果['测试']
英文:
I think you looking for this
text = "test string"words = ["test", "banana", "example"]found_words = [word for word in words if word in text]print(found_words)
result
['test']
答案2
得分: 0
我认为你应该这样做：
res = [x for x in z if x in y]
print(f"匹配: {', '.join(res) if res else '无'}")
输出
匹配: test
<details><summary>英文:</summary>I think you should do:
res = [x for x in z if x in y]
print(f"Match: {', '.join(res) if res else 'no'}")
Output
Match: test
</details># 答案3**得分**: 0你可以执行以下操作：y = "测试字符串"z = ["测试", "香蕉", "示例"]for x in z:if x in y:match_found = xprint("匹配项: " + match_found)break<details><summary>英文:</summary>You can do the below:y = "test string"z = ["test", "banana", "example"]for x in z:if x in y:match_found = xprint("Match: " + match_found)break</details># 答案4**得分**: 0可以使用filter和lambda函数：```python>>> list(filter(lambda x: x in y, z))['test']
英文:
you can use filter and lambda function:
>>> list(filter(lambda x: x in y, z))['test']
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