如何在循环中对文本中的数字进行排序

huangapple
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英文:

How to sequence numbers in text while looping

问题

我试图找到一种以特定方式打印数字的方法，但我无法做到，我的代码如下：

  1. for i in range(7): # 7 可以是字符串的长度，例如
  2.     print("letter"+str(i)+",letter"+str(i+1)+"|letter"+str(i+2)+",letter"+str(i+3)+";")

将打印出以下内容：

  1. letter0,letter1|letter1,letter2;
  2. letter1,letter2|letter2,letter3;
  3. letter2,letter3|letter3,letter4;
  4. letter3,letter4|letter4,letter5;
  5. letter4,letter5|letter5,letter6;
  6. letter5,letter6|letter6,letter7;
  7. letter6,letter7|letter7,letter8;

我需要的输出如下：

  1. letter0,letter1|letter2,letter3;
  2. letter4,letter5|letter6,letter7;
  3. letter8,letter9|letter10,letter11;
  4. letter12,letter13|letter0,letter1;

并且letter0; 应始终是最后一个。

英文:

I'm trying to reach a way to print numbers in a specific way but I can't, my code here

  1. for i in range(7): # 7 it could be a string length for an example
  2.     print("letter"+str(i)+",letter"+str(i+1)+"|letter"+str(i+1)+",letter"+str(i+2)+";")

will print:

  1. letter0,letter1|letter1,letter2;
  2. letter1,letter2|letter2,letter3;
  3. letter2,letter3|letter3,letter4;
  4. letter3,letter4|letter4,letter5;
  5. letter4,letter5|letter5,letter6;
  6. letter5,letter6|letter6,letter7;
  7. letter6,letter7|letter7,letter8;

What output I need is like this:

  1. letter0,letter1|letter1,letter2;
  2. letter2,letter3|letter3,letter4;
  3. letter4,letter5|letter5,letter6;
  4. letter6,letter7|letter7,letter8;
  5. letter8,letter9|letter9,letter10;
  6. letter10,letter11|letter11,letter12;
  7. letter12,letter13|letter13,letter0;

and letter0; should be the last one always

答案1

得分: 1

  1. result:
  3.     letter0,letter1|letter1,letter2
  4.     letter2,letter3|letter3,letter4
  5.     letter4,letter5|letter5,letter6
  6.     letter6,letter7|letter7,letter0
英文: 
  1. r = range(7)
  3. for a, b in [(i, i + 1) for i in r][::2]:
  4.     if b + 1 <= len(r):
  5.         c = b + 1
  6.     else:
  7.         c = 0
  8.     print(f"letter{a},letter{b}|letter{b},letter{c}")

result:

  1. letter0,letter1|letter1,letter2
  2. letter2,letter3|letter3,letter4
  3. letter4,letter5|letter5,letter6
  4. letter6,letter7|letter7,letter0

答案2

得分: 0

你可以在使用 print 时使用 end 参数。

  1. where = 0
  2. for i in range(14):
  3.     for _ in range(2):
  4.         where += 1
  5.         print(i, "|", end = "", sep = "")
  6.         if where == 4:
  7.             where = 0
  8.             print(";")
英文:

You can use the end argument when using print.

  1. where = 0
  2. for i in range(14):
  3.     for _ in range(2):
  4.         where += 1
  5.         print(i, "|", end = "", sep = "")
  6.         if where == 4:
  7.             where = 0
  8.             print(";")

答案3

得分: 0

也许类似这样的代码会起作用：

  1. for i in range(7): # 7 可以是一个字符串的长度示例
  2.     e = i + 1
  3.     f = i + 2
  4.     g = i
  5.     if i > 0:
  6.         g += i
  7.         f += i
  8.         e += i
  9.         if f == 14:
  10.             f = 0
  11.     print(f"letter{g}, letter{e}|letter{e},letter{f};")
英文:

Maybe something like that would work:

  1. for i in range(7): # 7 it could be a string length for an example
  2.     e = i + 1
  3.     f = i + 2
  4.     g = i
  5.     if i > 0:
  6.         g += i
  7.         f += i
  8.         e += i
  9.         if f == 14:
  10.             f = 0
  11.     print(f"letter{g}, letter{e}|letter{e},letter{f};")

答案4

得分: 0

使用字符串格式化增加可读性。使用模除运算修复最后迭代的索引。

  1. n = 7
  3. template = 'letter{},letter{}|letter{},letter{};'
  4. counter = 0
  5. for _ in range(n):
  6.     s = template.format(counter, counter+1, counter+1, (counter+2) % (2*n))
  7.     print(s)
  8.     counter += 2
英文:

Add readability with a string formatter. Use modulo arithmetic to fix the index of the last iteration.

  1. n = 7
  3. template = 'letter{},letter{}|letter{},letter{};'
  4. counter = 0
  5. for _ in range(n):
  6.     s = template.format(counter, counter+1, counter+1, (counter+2) % 2*n)
  7.     print(s)
  8.     counter += 2

huangapple
  • 本文由 发表于 2023年1月8日 22:59:07
  • 转载请务必保留本文链接：https://go.coder-hub.com/75048782.html
  • python
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