英文:
Remove the dictionary keys compare to list using python
问题
我正在尝试执行的实际操作是，我正在处理一个包含大量字典数据和变量的任务。我需要比较这些变量和字典，并移除与之相关的部分。例如：
我的变量是：("ken", "col", "PVS")
test_dict = {"Pant": 22, "Shirt": 21, "Col high": 21, "Ken-super": 21, "Ken": 82}
print("在执行移除之前的字典：\n" + str(test_dict))
a_dict = {key: test_dict[key] for key in test_dict if key != 'Ken'}
print("执行移除之后的字典：\n", a_dict)
如果我运行上述代码，它只会从 test_dict 中移除 ken。我需要移除那些包含在我的 words 变量中的单词，同时也需要移除与我的 words 变量相似的单词。比如，需要移除 Ken-super 和 col High。
我期望的输出是：{'Pant': 22, 'Shirt': 21}。就是这样。我期望移除与我的字典相似的单词。
英文:
Actual what I'm trying to perform, I working to with big dictionary data and variables . I need to compare the variables and dict and remove the which as relate to same. Eg:-
My words = ("ken",col","PVS")
test_dict = {"Pant": 22, "Shirt": 21, "Col high": 21, "Ken-super": 21, "Ken": 82}
print("The dictionary before performing remove is : \n" + str(test_dict))
a_dict = {key: test_dict[key] for key in test_dict if key != 'Ken'}
print("The dictionary after performing remove is : \n", a_dict)
If i run above code it will remove only ken only from test_dict. I need to remove the words which as contain on my words variable and also i need to remove the similar to my words variable. Like need to remove Ken-super,col High too
I need output like
{'Pant': 22, 'Shirt' : 21} only.
That's it
My expecting the output of Remove the similar words which compare to my dict
答案1
得分: 2
这将帮助你获得你想要的结果。
bad_words = ("ken", "col", "PVS")
test_dict = {"Pant": 22, "Shirt": 21, "Col high": 21, "Ken-super": 21, "Ken": 82}
new_dict = {key: value for key, value in test_dict.items() if not any(word in key.lower() for word in bad_words)}
print(new_dict)
英文:
This should get you what you want.
bad_words = ("ken","col","PVS")
test_dict = {"Pant": 22, "Shirt": 21, "Col high": 21, "Ken-super": 21, "Ken": 82}
new_dict = {key: value for key, value in test_dict.items() if not any(word in key.lower() for word in bad_words)}
print(new_dict)
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