英文:
How to replace array of object containing ids with the data using MongoDB aggregation
问题
我有一个包含以下数据的集合,并希望得到下面我提到的理想输出。
db={
collectionA: [
{
"id": ObjectId("63b7c24c06ebe7a8fd11777b"),
"uniqueRefId": "UUID-2023-0001",
"products": [
{
"productIndex": 1,
"productCategory": ObjectId("63b7c24c06ebe7a8fd11777b"),
"productOwners": [
ObjectId("63b7c2fd06ebe7a8fd117781")
]
},
{
"productIndex": 2,
"productCategory": ObjectId("63b7c24c06ebe7a8fd11777b"),
"productOwners": [
ObjectId("63b7c2fd06ebe7a8fd117781"),
ObjectId("63b7c12706ebe7a8fd117778")
]
},
{
"productIndex": 3,
"productCategory": "",
"productOwners": ""
}
]
}
],
collectionB: [
{
"_id": ObjectId("63b7c2fd06ebe7a8fd117781"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
},
{
"_id": ObjectId("63b7c12706ebe7a8fd117778"),
"fullname": "Carry Minatti",
"email": "carry.minatty@pp.com"
},
]
}
Desirable Output = [
{
"id": ObjectId("507f1f77bcf86cd799439011"),
"uniqueRefId": "UUID-2023-0001",
"products": [
{
"productIndex": 1,
"productCategory": ObjectId('614g2f77bff86cd755439021'),
"productOwners": [
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41acd"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
}
]
},
{
"productIndex": 2,
"productCategory": ObjectId('614g2f77bff86cd755439021'),
"productOwners": [
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41acd"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
},
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41ace"),
"fullname": "Carry Minatti",
"email": "carry.minatty@pp.com"
}
]
},
{
"productIndex": 3,
"productCategory": "",
"productOwners": ""
}
]
}
]
在collectionA中,我们还有其他文档,不仅仅是一个文档。collectionB也有其他文档。
我们如何可以获得这个理想的输出?
我期望得到用于获得这个解决方案的MongoDB查询。
我已经实现了类似以下的lookup:
db.collectionA.aggregate([
{
"$lookup": {
"from": "collectionB",
"localField": "products.productOwners",
"foreignField": "_id",
"as": "inventory_docs"
}
}
])
英文:
I am having a collection which contains the data like the following and want to have the desirable output which I have mentioned below.
db={
collectionA: [
{
"id": ObjectId("63b7c24c06ebe7a8fd11777b"),
"uniqueRefId": "UUID-2023-0001",
"products": [
{
"productIndex": 1,
"productCategory": ObjectId("63b7c24c06ebe7a8fd11777b"),
"productOwners": [
ObjectId("63b7c2fd06ebe7a8fd117781")
]
},
{
"productIndex": 2,
"productCategory": ObjectId("63b7c24c06ebe7a8fd11777b"),
"productOwners": [
ObjectId("63b7c2fd06ebe7a8fd117781"),
ObjectId("63b7c12706ebe7a8fd117778")
]
},
{
"productIndex": 3,
"productCategory": "",
"productOwners": ""
}
]
}
],
collectionB: [
{
"_id": ObjectId("63b7c2fd06ebe7a8fd117781"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
},
{
"_id": ObjectId("63b7c12706ebe7a8fd117778"),
"fullname": "Carry Minatti",
"email": "carry.minatty@pp.com"
},
]
}
Desirable Output = [
{
"id": ObjectId("507f1f77bcf86cd799439011"),
"uniqueRefId": "UUID-2023-0001",
"products": [
{
"productIndex": 1,
"productCategory": ObjectId('614g2f77bff86cd755439021'),
"productOwners": [
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41acd"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
}
]
},
{
"productIndex": 2,
"productCategory": ObjectId('614g2f77bff86cd755439021'),
"productOwners": [
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41acd"),
"fullname": "Jim Corbett",
"email": "jim.corbett@pp.com"
},
{
"_id": ObjectId("63ac1e59c0afb8b6f2d41ace"),
"fullname": "Carry Minatti",
"email": "carry.minatty@pp.com"
}
]
},
{
"productIndex": 3,
"productCategory": "",
"productOwners": ""
}
]
}
]
In the collectionA we are having other documents as well, its not just one document.
Similarly for collectionB we are having other documents too.
How we can get this desirable output?
I am expecting the mongodb query for getting this solution.
I have implemented the lookup like the following
db.collectionA.aggregate([
{
"$lookup": {
"from": "collectionB",
"localField": "products.productOwners",
"foreignField": "_id",
"as": "inventory_docs"
}
}
])
答案1
得分: 0
你可以尝试这样做:
db.collectionA.aggregate([
{
"$unwind": "$products"
},
{
"$lookup": {
"from": "collectionB",
"localField": "products.productOwners",
"foreignField": "_id",
"as": "products.productOwners"
}
},
{
"$group": {
"_id": {
id: "$id",
uniqueRefId: "$uniqueRefId"
},
"products": {
"$push": "$products"
}
}
},
{
"$project": {
id: "$_id.id",
uniqueRefId: "$_id.uniqueRefId",
products: 1,
_id: 0
}
}
])
在这个查询中,我们执行以下操作:
- 首先,使用
$unwind
展开products
数组。 - 然后,使用
$lookup
计算productOwners
。 - 接下来,使用
$group
对展开的元素进行分组。 - 最后,使用
$project
投影所需的输出。
英文:
You can try this:
db.collectionA.aggregate([
{
"$unwind": "$products"
},
{
"$lookup": {
"from": "collectionB",
"localField": "products.productOwners",
"foreignField": "_id",
"as": "products.productOwners"
}
},
{
"$group": {
"_id": {
id: "$id",
uniqueRefId: "$uniqueRefId"
},
"products": {
"$push": "$products"
}
}
},
{
"$project": {
id: "$_id.id",
uniqueRefId: "$_id.uniqueRefId",
products: 1,
_id: 0
}
}
])
In this query, we do the following:
- First we unwind the
products
array, using$unwind
. - Then we calculate
productOwners
, using$lookup
. - Then we group the unwinded elements, using
$group
. - Finally we, project the desired output using
$project
.
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