如何解析嵌套的XML？

huangapple
go评论131阅读模式
英文:

How to unmarshall nested XML?

问题

我有一个名为config-test.xml的XML文件，我想要进行解组：

  1. <configuration version="37">
  2.   <folder id="0usj3" label="aaa" type="sendreceive">
  3.     <device id="U34L32N"></device>
  4.     <device id="U34L32NXX"></device>
  5.     <device id="U34L32NYY"></device>
  6.   </folder>
  7.   <folder id="0usj4" label="bbb" type="sendreceive">
  8.     <device id="U34L32NYY"></device>
  9.   </folder>
  10.   <device id="U34L32N" name="wazaa"></device>
  11.   <device id="FJP7437" name="wazii"></device>
  12. </configuration>

我正在使用以下代码进行解组：

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"io"
  7. 	"os"
  9. 	"github.com/rs/zerolog/log"
  10. )
  12. type Device struct {
  13. 	ID   string `xml:"id,attr"`
  14. 	Name string `xml:"name,attr"`
  15. }
  17. type Folder struct {
  18. 	ID     string `xml:"id,attr"`
  19. 	Label  string `xml:"label,attr"`
  20. 	Type   string `xml:"type,attr"`
  21. 	Device []Device
  22. }
  24. type Configuration struct {
  25. 	Folder []Folder `xml:"folder"`
  26. 	Device []Device `xml:"device"`
  27. }
  29. func main() {
  30. 	var err error
  32. 	xmlFile, errOpen := os.Open("config-test.xml")
  33. 	byteValue, errRead := io.ReadAll(xmlFile)
  34. 	if errOpen != nil || errRead != nil {
  35. 		log.Fatal().Msgf("无法打开（%v）或读取（%v）config.xml：%v", errOpen, errRead)
  36. 	}
  37. 	defer xmlFile.Close()
  39. 	config := Configuration{}
  40. 	err = xml.Unmarshal(byteValue, &config)
  41. 	if err != nil {
  42. 		log.Fatal().Msgf("无法解组XML：%v", err)
  43. 	}
  45. 	fmt.Printf("%v", config)
  46. }

我得到了一个部分结果：

  1. {[{0usj3 aaa sendreceive []} {0usj4 bbb sendreceive []}] [{U34L32N wazaa} {FJP7437 wazii}]}

这是部分结果，因为XML被正确解析，但嵌套在<folder>中的<device>条目没有被考虑进去。

是否有特殊的方式来声明这些嵌套元素？

英文:

I have the following XML file (config-test.xml) that I would to unmarshall:

  1. <configuration version="37">
  2.   <folder id="0usj3" label="aaa" type="sendreceive">
  3.     <device id="U34L32N"></device>
  4.     <device id="U34L32NXX"></device>
  5.     <device id="U34L32NYY"></device>
  6.   </folder>
  7.   <folder id="0usj4" label="bbb" type="sendreceive">
  8.     <device id="U34L32NYY"></device>
  9.   </folder>
  10.   <device id="U34L32N" name="wazaa"></device>
  11.   <device id="FJP7437" name="wazii"></device>
  12. </configuration>

This is the code I am using for that:

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"io"
  7. 	"os"
  9. 	"github.com/rs/zerolog/log"
  10. )
  12. type Device struct {
  13. 	ID   string `xml:"id,attr"`
  14. 	Name string `xml:"name,attr"`
  15. }
  17. type Folder struct {
  18. 	ID     string `xml:"id,attr"`
  19. 	Label  string `xml:"label,attr"`
  20. 	Type   string `xml:"type,attr"`
  21. 	Device []Device
  22. }
  24. type Configuration struct {
  25. 	Folder []Folder `xml:"folder"`
  26. 	Device []Device `xml:"device"`
  27. }
  29. func main() {
  30. 	var err error
  32. 	xmlFile, errOpen := os.Open("config-test.xml")
  33. 	byteValue, errRead := io.ReadAll(xmlFile)
  34. 	if errOpen != nil || errRead != nil {
  35. 		log.Fatal().Msgf("cannot open (%v) or read (%v) config.xml: %v", errOpen, errRead)
  36. 	}
  37. 	defer xmlFile.Close()
  39. 	config := Configuration{}
  40. 	err = xml.Unmarshal(byteValue, &config)
  41. 	if err != nil {
  42. 		log.Fatal().Msgf("cannot unmarshall XML: %v", err)
  43. 	}
  45. 	fmt.Printf("%v", config)
  46. }

I get a partial result:

  1. {[{0usj3 aaa sendreceive []} {0usj4 bbb sendreceive []}] [{U34L32N wazaa} {FJP7437 wazii}]}

It is partial because the XML was parsed correctly, but the <device> entries nested in <folder> were not accounted for.

Is there a special way I should decalre these nested elements?

答案1

得分: 2

Folder中的Device缺少注释。

  1. type Folder struct {
  2. 	ID     string   `xml:"id,attr"`
  3. 	Label  string   `xml:"label,attr"`
  4. 	Type   string   `xml:"type,attr"`
  5. 	Device []Device `xml:"device"`
  6. }
英文:

The annotation is missing on Device in Folder.

  1. type Folder struct {
  2. 	ID     string   `xml:"id,attr"`
  3. 	Label  string   `xml:"label,attr"`
  4. 	Type   string   `xml:"type,attr"`
  5. 	Device []Device `xml:"device"`
  6. }

huangapple
  • 本文由 发表于 2023年1月5日 00:55:19
  • 转载请务必保留本文链接：https://go.coder-hub.com/75008717.html
  • go
  • nested
  • xml
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