英文:
Go Colly how to find requested element?
问题
我正在尝试使用colly来循环遍历特定表格的内容，但是该表格没有被识别出来，以下是我目前的代码：
package main
import (
"fmt"
"github.com/gocolly/colly"
)
func main() {
c := colly.NewCollector(
colly.AllowedDomains("wikipedia.org", "en.wikipedia.org"),
)
links := make([]string, 0)
c.OnHTML("div.mw-parser-output", func(e *colly.HTMLElement) {
e.ForEach("table.wikitable.sortable.jquery-tablesorter > tbody > tr", func(_ int, elem *colly.HTMLElement) {
fmt.Println(elem.ChildAttr("a[href]", "href"))
links = append(links, elem.ChildAttr("a[href]", "href"))
})
})
c.OnRequest(func(r *colly.Request) {
fmt.Println("Visiting", r.URL.String())
})
c.Visit("https://en.wikipedia.org/wiki/List_of_countries_and_dependencies_by_population")
fmt.Println("Found urls for", len(links), "countries.")
}
我需要循环遍历表格中的所有tr元素。
英文:
I'm trying to get specific table to loop through its content using colly but table its not being recognized, here's what I have so far.
package main
import (
"fmt"
"github.com/gocolly/colly"
)
func main() {
c := colly.NewCollector(
colly.AllowedDomains("wikipedia.org", "en.wikipedia.org"),
)
links := make([]string, 0)
c.OnHTML("div.mw-parser-output", func(e *colly.HTMLElement) {
e.ForEach("table.wikitable.sortable.jquery-tablesorter > tbody > tr", func(_ int, elem *colly.HTMLElement) {
fmt.Println(elem.ChildAttr("a[href]", "href"))
links = append(links, elem.ChildAttr("a[href]", "href"))
})
})
c.OnRequest(func(r *colly.Request) {
fmt.Println("Visiting", r.URL.String())
})
c.Visit("https://en.wikipedia.org/wiki/List_of_countries_and_dependencies_by_population")
fmt.Println("Found urls for", len(links), "countries.")
}
I need to loop thought all of the tr elements in the the table.
答案1
得分: 1
原来类的名称实际上是wikitable.sortable，尽管在Chrome控制台中显示为wikitable sortable jquery-tablesorter。我不知道为什么名称会有这样的差异，但这解决了我的问题。
英文:
Turns out name of the class is actually wikitable.sortable even though in chrome console is shown as wikitable sortable jquery-tablesorter. I dont know why the names are different like this but it solved the problem for me.
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