英文:
Is there anyway to make the return text of a boolean function not show in the terminal
问题
我正在为学校做一个项目，需要使用二分查找来判断一个特定的数字是否存在于一串数字中。我对编程还很陌生，正在尝试找到一种方法，让"true"不在终端中显示出来。有没有办法做到这一点，还是我必须删除布尔函数？我知道不能从代码中删除"return true"，因为这会导致它停止工作，但我希望输出只是我打印的代码，而不是"true"。
func BinarySearch(target int, input []int) bool {
first := 0
last := len(input) - 1
for first <= last{
median := (first + last) / 2
if input[median] < target {
first = median + 1
}else{
last = median - 1
}
}
if first == len(input) || input[first] != target {
fmt.Println("The searched integer", target, "was not found")
} else {
fmt.Println("The searched integer", target, "was found")
}
return true
}
我已经输入了我想要打印的文本，但不知道该如何处理返回值。
英文:
Im doing a project for school where I have to use binary search to figure out if a specific number is present in a string of numbers. I am new to coding and am trying to figure out a way to have "true" not show up in the terminal. Is there a way to do this or do I have to remove the boolean function. I know I cannot remove the "return true" from the code because it stops it from working but I want the output to just be the code I am printing not the "true"
func BinarySearch(target int, input []int) bool {
first := 0
last := len(input) - 1
for first <= last{
median := (first + last) / 2
if input[median] < target {
first = median + 1
}else{
last = median - 1
}
}
if first == len(input) || input[first] != target {
fmt.Println("The searched integer", target, "was not found")
} else {
fmt.Println("The searched integer", target, "was found")
}
return true
}
I have input the text I want to print but do not know what to do about the return
答案1
得分: 1
你可以通过在函数参数后面删除bool关键字来实现这一点，因为基本上你是在告诉函数必须返回一个布尔值，而你将要将其用作void。在将输入传递给函数之前，不要忘记对其进行预排序。祝你好运。
func BinarySearch(target int, input []int) {
first := 0
last := len(input) - 1
for first <= last{
median := (first + last) / 2
if input[median] < target {
first = median + 1
}else{
last = median - 1
}
}
if first == len(input) || input[first] != target {
fmt.Println("要查找的整数", target, "未找到")
} else {
fmt.Println("要查找的整数", target, "已找到")
}
}
英文:
You can just do that by removing the bool after the params of the function, because basically you were telling that the function must return a boolean, while you were going to use it as a void. Dont forget also to pre-sort your input prior to passing it to your function. Best of luck
func BinarySearch(target int, input []int) {
first := 0
last := len(input) - 1
for first <= last{
median := (first + last) / 2
if input[median] < target {
first = median + 1
}else{
last = median - 1
}
}
if first == len(input) || input[first] != target {
fmt.Println("The searched integer", target, "was not found")
} else {
fmt.Println("The searched integer", target, "was found")
}
}
答案2
得分: 0
我可能会这样做：
package main
import (
"fmt"
)
func main() {
orderedList := []int{1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25}
for i := 0; i < 27; i++ {
var slug string
if found := BinarySearch(i, orderedList); !found {
slug = "不"
}
fmt.Printf("%d 在列表中%s存在\n", i, slug)
}
}
func BinarySearch(target int, values []int) (found bool) {
lo := 0
hi := len(values)
for hi > lo {
mid := lo + (hi-lo)/2
if values[mid] < target {
lo = mid + 1
} else {
hi = mid
}
}
found = lo < len(values) && target == values[lo]
return found
}
这是一个使用二分查找算法的示例代码，它在一个有序列表中查找给定的目标值。代码中使用了一个名为BinarySearch的函数来执行二分查找操作，并在main函数中进行了测试。
英文:
I would probably do something like this:
https://goplay.tools/snippet/vBgmo4ASUh5
package main
import (
"fmt"
)
func main() {
orderedList := []int{1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25}
for i := 0; i < 27; i++ {
var slug string
if found := BinarySearch(i, orderedList); !found {
slug = "not "
}
fmt.Printf("%d is %s in the list\n", i, slug)
}
}
func BinarySearch(target int, values []int) (found bool) {
lo := 0
hi := len(values)
for hi > lo {
mid := lo + (hi-lo)/2
if values[mid] < target {
lo = mid + 1
} else {
hi = mid
}
}
found = lo < len(values) && target == values[lo]
return found
}
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