英文:
How to change instance type in EC2 Launch Template using AWS SDK?
问题
我正在寻找更改启动模板中某些内容的方法，例如实例类型。这意味着在此过程中创建一个新版本。
我已经查阅了Go和Python的SDK文档，但似乎都没有提供相应的参数来实现这一目标。
请帮助我解决这个问题...
英文:
I'm looking to change certain things in the launch template e.g. the instance type. Which means creating a new version while doing so.
I have gone through the SDK documentation for both Go and Python. Neither seem to have the paramenters that'd let me acheive the same.
I'm refering to these:
Go's function,
Python's function
Please help me out...
答案1
得分: 2
EC2启动模板是不可变的。如果需要修改当前启动模板版本，必须创建一个新版本。
以下是使用AWS SDK v2创建新版本并将其设置为默认版本的示例。
安装以下两个包：
"github.com/aws/aws-sdk-go-v2/service/ec2"ec2types "github.com/aws/aws-sdk-go-v2/service/ec2/types"
假设您已创建了AWS配置：
func createLaunchTemplateVersion(cfg aws.Config) {ec2client := ec2.NewFromConfig(cfg)template := ec2types.RequestLaunchTemplateData{InstanceType: ec2types.InstanceTypeT2Medium}createParams := ec2.CreateLaunchTemplateVersionInput{LaunchTemplateData: &template,LaunchTemplateName: aws.String("MyTemplate"),SourceVersion: aws.String("1"),}outputCreate, err := ec2client.CreateLaunchTemplateVersion(context.Background(), &createParams)if err != nil {log.Fatal(err)}if outputCreate.Warning != nil {log.Fatalf("%v\n", outputCreate.Warning.Errors)}// 将新的启动模板版本设置为默认版本modifyParams := ec2.ModifyLaunchTemplateInput{DefaultVersion: aws.String(strconv.FormatInt(*outputCreate.LaunchTemplateVersion.VersionNumber, 10)),LaunchTemplateName: outputCreate.LaunchTemplateVersion.LaunchTemplateName,}outputModify, err := ec2client.ModifyLaunchTemplate(context.Background(), &modifyParams)if err != nil {log.Fatal(err)}fmt.Printf("默认版本 %d\n", *outputModify.LaunchTemplate.DefaultVersionNumber)}
英文:
EC2 launch template is immutable. You must create a new version if you need to modify the current launch template version.
Here is an example of creating a new version and then making it the default version using AWS SDK v2.
Install these two packages:
"github.com/aws/aws-sdk-go-v2/service/ec2"ec2types "github.com/aws/aws-sdk-go-v2/service/ec2/types"
Assuming you created the AWS config:
func createLaunchTemplateVersion(cfg aws.Config) {ec2client := ec2.NewFromConfig(cfg)template := ec2types.RequestLaunchTemplateData{InstanceType: ec2types.InstanceTypeT2Medium}createParams := ec2.CreateLaunchTemplateVersionInput{LaunchTemplateData: &template,LaunchTemplateName: aws.String("MyTemplate"),SourceVersion: aws.String("1"),}outputCreate, err := ec2client.CreateLaunchTemplateVersion(context.Background(), &createParams)if err != nil {log.Fatal(err)}if outputCreate.Warning != nil {log.Fatalf("%v\n", outputCreate.Warning.Errors)}// set the new launch type version as the default versionmodifyParams := ec2.ModifyLaunchTemplateInput{DefaultVersion: aws.String(strconv.FormatInt(*outputCreate.LaunchTemplateVersion.VersionNumber, 10)),LaunchTemplateName: outputCreate.LaunchTemplateVersion.LaunchTemplateName,}outputModify, err := ec2client.ModifyLaunchTemplate(context.Background(), &modifyParams)if err != nil {log.Fatal(err)}fmt.Printf("default version %d\n", *outputModify.LaunchTemplate.DefaultVersionNumber)}
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