英文:
count slice length in struct field
问题
我认为我需要一个比我的case switch更好的解决方案,因为当结构体增加更多字段时,我的函数会变得冗长。有没有一种方法可以用循环替换我的switch?
我有以下代码:
type Things struct {
StreetNames []string `json:"streetNames"`
Letters []string `json:"letters"`
MaleNames []string `json:"maleNames"`
}
func CheckCategories(data *Things, filePath string) error {
errMsg := "list has no values or is a missing category in File: " + filePath
categories := []string{"street_name", "letter", "male_first_name"}
for _, value := range categories {
switch value {
case "street_name":
if len(data.StreetNames) == 0 {
return errors.New("street_name " + errMsg)
}
case "letter":
if len(data.Letters) == 0 {
return errors.New("letter " + errMsg)
}
case "male_first_name":
if len(data.MaleNames) == 0 {
return errors.New("male_first_name " + errMsg)
}
}
}
return nil
}
这对我来说是有效的,但是真正的结构体包含12个字段,这使得我的函数变得冗长和重复。
我尝试过:
for _, value := range categories {
if len("data." + value) == 0 {
return errors.New(value + errMsg)
}
}
但当我运行代码时,我花了一些时间才注意到它没有按预期工作,我得到的是字符串的长度。我尝试过data[value]
,但也没有起作用。
英文:
I think I need a better solution than my case switch as the struct gains more fields my function will become verbose. Is there a way to swap my switch for a loop?
I have the following code
type Things struct {
StreetNames []string `json:"streetNames"`
Letters []string `json:"letters"`
MaleNames []string `json:"maleNames"`
}
func CheckCategories(data *Things, filePath string) error {
errMsg := "list has no values or is a missing category in File: " + filePath
categories := []string{"street_name", "letter", "male_first_name"}
for _, value := range categories {
switch value {
case "street_name":
if len(data.StreetNames) == 0 {
return errors.New("street_name " + errMsg)
}
case "letter":
if len(data.Letters) == 0 {
return errors.New("letter " + errMsg)
}
case "male_first_name":
if len(data.MaleNames) == 0 {
return errors.New("male_first_name " + errMsg)
}
}
}
return nil
}
This works for me but the real struct contains 12 fields which makes my functions long and repetitive.
I tried
for _, value := range categories {
if len("data." + value) == 0 {
return errors.New(value + errMsg)
}
But when I ran the code I took a moment to notice it wasn't working as intended, Im getting the length of the string. I have tried data[value] but that didn't work either.
答案1
得分: 1
有一种方法可以将我的开关换成一个循环吗?
你可以这样做:
type Things struct {
StreetNames []string `json:"streetNames"`
Letters []string `json:"letters"`
MaleNames []string `json:"maleNames"`
}
func CheckCategories(data *Things, filePath string) error {
errMsg := "list has no values or is a missing category in File: " + filePath
categories := []struct{
name string
slice []string
}{
{"street_name", data.StreetNames},
{"letter", data.Letters},
{"male_first_name", data.MaleNames},
}
for _, v := range categories {
if len(v.slice) == 0 {
return errors.New(v.name + " " + errMsg)
}
}
return nil
}
英文:
> Is there a way to swap my switch for a loop?
You could do the following:
type Things struct {
StreetNames []string `json:"streetNames"`
Letters []string `json:"letters"`
MaleNames []string `json:"maleNames"`
}
func CheckCategories(data *Things, filePath string) error {
errMsg := "list has no values or is a missing category in File: " + filePath
categories := []struct{
name string
slice []string
}{
{"street_name", data.StreetNames},
{"letter", data.Letters},
{"male_first_name", data.MaleNames},
}
for _, v := range categories {
if len(v.slice) == 0 {
return errors.New(v.name + " " + errMsg)
}
}
return nil
}
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