英文:
Regex to match content inside curly braces
问题
我正在尝试创建一个正则表达式，以提取花括号之间的任何单词（字母数字），如下面的示例所示：
Hi {{ name }}, your full name is {{ concat first_name last_name }}
条件如下：
- 如果花括号内的内容只包含连续的字母数字，那么它是一个变量，应该被提取出来。
- 如果花括号内的内容包含多个由空格分隔的字母数字，那么第一个出现的是函数名，应该被忽略，但是剩下的参数（函数参数）应该被提取出来。
- 每个函数参数由空格分隔。
- 每个变量名可以包含多个单词，但是变量名中的每个单词应该使用分隔符连接，例如：first_name。
- 函数参数可以有一个或多个参数，每个参数都应该匹配。
所以第一个示例的结果应该是：
name, first_name, last_name.
这是我尝试的正则表达式：\{\s*\{\s*([^\}\/\s]+)\s*\}\s*\}
但它只涵盖了第一种情况。
另一个示例：
"Key": "price_change_manager.msg2 {{ message }}"
"value": "{{ username }} plan to {{formatCurrence new_price currency old_price }}"
应该匹配：message, username, new_price, currency, old_price.
英文:
I'm trying to make a regex to extract any word (alphanumeric) between curly brackets as in the example bellow:
> Hi {{ name }}, your full name is {{ concat first_name last_name }}
The conditions are:
- if the content inside contains only a sequential alpha_numeric, that means it is a variable and should be extracted.
- if the content inside contains more than one alpha_numeric separated by space, that means the first occurrence is a function name and should be ignored, but the remaining arguments (function arguments) should be extracted.
- each function argument is separated by space.
- each variable name can contain more than one word, but each word in the variable name should be connected using a separator, e.g: first_name
- the function arguments can have one or many arguments and each argument should be matched.
So the result for the first example should be:
name, first_name, last_name.
This is what I tried: \{\s*\{\s*([^\}\/\s]+)\s*\}\s*\}
But it only covers the first scenario.
Another example:
"Key": "price_change_manager.msg2 {{ message }}"
value": "{{ username }} plan to {{formatCurrence new_price currency old_price }}"
Should match: message, username, new_price, currency, old_price.
答案1
得分: 1
一个不是特别过度设计的正则表达式，带有一些条件语句，可以完成工作，例如：
re := regexp.MustCompile(`\{\{ *([a-zA-Z_]+|[a-zA-Z_]+(( +[a-zA-Z_]+)+)) *\}\}`)
matches := re.FindAllStringSubmatch("{{ username }} plan to {{formatCurrence new_price currency old_price }}", -1)
这将得到一个类似的切片：
[["{{ username }}" "username" "" ""] ["{{formatCurrence new_price currency old_price }}" "formatCurrence new_price currency old_price" " new_price currency old_price" " old_price"]]
因此，你可以像这样处理它：
findings := []string{}
for _, m := range matches {
if m[2] == "" {
// 当第三个元素为空时，它是一个单个匹配，在第二个元素中
findings = append(findings, m[1])
} else {
// 否则，它是一个多个匹配，在第三个元素中的一个字符串
// 分割它，然后将它们附加到结果中
findings = append(findings, strings.Split(strings.Trim(m[2], " "), " ")...)
}
}
// 你的结果在findings中
英文:
A not particularly overengineered regexp with some ifs does do job, like:
re := regexp.MustCompile(`\{\{ *([a-zA-Z_]+|[a-zA-Z_]+(( +[a-zA-Z_]+)+)) *\}\}`)
matches := re.FindAllStringSubmatch("{{ username }} plan to {{formatCurrence new_price currency old_price }}", -1)
This will result a slice like:
[["{{ username }}" "username" "" ""] ["{{formatCurrence new_price currency old_price }}" "formatCurrence new_price currency old_price" " new_price currency old_price" " old_price"]]
So you can process it like:
findings := []string{}
for _, m := range matches {
if m[2] == "" {
// When the 3rd element is empty then it's a single match, in the 2nd element
findings = append(findings, m[1])
} else {
// Otherwise it's multi match, in one string in the 3rd element
// Split it and then append them
findings = append(findings, strings.Split(strings.Trim(m[2], " "), " ")...)
}
}
// Your result is in findings
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