Why golang map solution O(1) is slower than loop solution O(n) solution?

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英文:

Why golang map solution O(1) is slower than loop solution O(n) solution?

问题

我正在为您翻译以下内容:

我正在解决力扣题目最大的 69 数,并想出了两种解决方案。

  1. 创建一个包含所有可能答案的映射表,并根据输入返回映射表中的值。(6毫秒)
  2. 从左边开始循环遍历数字。如果遇到6,就加上3 * 10^x。(2毫秒)

我理解的是,Golang 的 map 使用哈希表,平均时间复杂度应该是 O(1)。那么为什么 O(1) 的解法比循环的解法更慢呢?

另一个问题是:在程序运行时,我如何检查程序?我能否追踪堆栈和堆的历史记录?

func maximum69Number(num int) int {
    return map[int]int{
        6666: 9666,
        9666: 9966,
        6966: 9966,
        9966: 9996,
        6696: 9696,
        9696: 9996,
        6996: 9996,
        9996: 9999,
        6669: 9669,
        9669: 9969,
        6969: 9969,
        9969: 9999,
        6699: 9699,
        9699: 9999,
        6999: 9999,
        9999: 9999,
        666: 966,
        669: 969,
        696: 996,
        699: 999,
        966: 996,
        969: 999,
        996: 999,
        999: 999,

        66: 96,
        69: 99,
        96: 99,
        99: 99,

        6: 9,
        9: 9,
    }[num]
}
func maximum69Number(num int) int {
    m := 1000
    for m > 0 {
        n := num / m % 10
        if n == 6 {
            return num + 3 * m
        }

        m /= 10
    }
    return num
}
英文:

I was solving leetcode maximum69Number and I came up with 2 solutions.

  1. Create a map with all the possible answers and just return the value in the map by input. (6ms)
  2. Loop from the digit from the left. If you see a 6, add 3 * 10^x. (2ms)

My understanding is golang map is using hashmap and should be O(1) average. How could we explain that the O(1) solution is slower than the loop solution?

Another question is: how could I examine a program while it's running? Am I able to trace stack and heap history some how?

func maximum69Number (num int) int {
    return map[int]int{
        6666: 9666,
        9666: 9966,
        6966: 9966,
        9966: 9996,
        6696: 9696,
        9696: 9996,
        6996: 9996,
        9996: 9999,
        6669: 9669,
        9669: 9969,
        6969: 9969,
        9969: 9999,
        6699: 9699,
        9699: 9999,
        6999: 9999,
        9999: 9999,
        666: 966,
        669: 969,
        696: 996,
        699: 999,
        966: 996,
        969: 999,
        996: 999,
        999: 999,

        66: 96,
        69: 99,
        96: 99,
        99: 99,

        6: 9,
        9: 9,
    }[num]
}
func maximum69Number (num int) int {
    m := 1000
    for m > 0 {
        n := num / m % 10
        if n == 6 {
            return num + 3 * m
        }

        m /= 10
    }
    return num
}

答案1

得分: 1

程序的复杂性对于像这样的小输入并不会对运行时间产生太大影响。程序的复杂性衡量的是随着更大输入的增加,运行时间的增长速度,而不是提供一个准确的运行时间测量,这还取决于不同操作的常数。

英文:

The complexity of a program doesn't affect the running time that much with small inputs like this. The complexity of a program measures how fast the running time grows with bigger inputs instead of providing an exact measurement of the running time which depends also on the constant of different operations.

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  • 本文由 发表于 2022年11月8日 10:19:35
  • 转载请务必保留本文链接:https://go.coder-hub.com/74355029.html
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