why does time.Date() give different results when using hardcoded int values vs the values returned by another time.Date()?

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英文:

why does time.Date() give different results when using hardcoded int values vs the values returned by another time.Date()?

问题

我正在尝试从一个API中检索数据,其中我的请求必须具有开始和结束的Unix时间戳,但是我使用的方法得到了非常奇怪的结果。

(我将在示例中使用基于Go Playground的日期,它始终将time.Now().UTC()报告为2009-11-10 23:00:00)

我将安排每天运行此任务,并希望它始终检索两天前的所有记录,因此我需要发送一个开始时间为2009-11-08 00:00:00和结束时间为2009-11-08 23:59:59。

以下是我的方法摘要:

// 获取当前的UTC时间
now := time.Now().UTC()

// 从当前时间减去两天
twoDaysAgo := now.AddDate(0, 0, -2)

// 分别提取天、月和年,用于“重建”或“重置”我们的时间为00:00:00
day, month, year := twoDaysAgo.Date()

// 使用提取的天、月和年构建开始时间
startTime := time.Date(year, month, day, 0, 0, 0, 0, time.UTC)

当打印startTime时,我期望得到2009-11-08 00:00:00,但实际得到的是0014-05-02 00:00:00

Playground链接

package main

import (
	"fmt"
	"time"
)

func main() {
	// 我们试图在指定的日期上“重置时间”,即从今天开始过去的两天。
	// 这个time.Time将作为我们要进行请求的“开始”时间戳。

	// 首先,获取当前时间,Go Playground中硬编码为2009-11-10 23:00:00,并打印预期值
	now := time.Now().UTC()
	fmt.Println("当前时间:", now)

	// 减去两天,应该是2009-11-08 23:00:00,并打印预期值
	twoDaysAgo := now.AddDate(0, 0, -2)
	fmt.Println("两天前:", twoDaysAgo)

	// 从twoDaysAgo中提取天、月和年,应该是2009年11月8日
	// 这将打印预期值,以确认day、month和year包含我们需要的内容
	day, month, year := twoDaysAgo.Date()
	fmt.Println("提取的天、月和年:", day, month, year)

	// 使用time.Date()创建一个新的time.Time,以便将时间“重置”为00:00:00
	// 我们使用之前提取的day、month和year作为参数来实现这一点。
	// 这将打印出一个极不准确的日期0014-05-02 00:00:00,原因我不明白。
	dateFromDateExtraction := time.Date(year, month, day, 0, 0, 0, 0, time.UTC)
	fmt.Println("这个日期很奇怪:", dateFromDateExtraction)

	// 如果我们硬编码time.Date()的参数,
	// 结果将符合预期,这将打印出2009-11-08 00:00:00
	dateHardcoded := time.Date(2009, time.November, 8, 0, 0, 0, 0, time.UTC)
	fmt.Println("这个日期符合预期:", dateHardcoded)
}
英文:

I am trying to retrieve data from an API in which my request must have a start and end unix timestamp, and I a getting really strange results with my methodology.

(I'll use dates in my example based on the Go Playground, which always reports time.Now().UTC() as 2009-11-10 23:00:00)

I will be scheduling this to run daily, and I'd like it to always retrieve all records from 2 days ago, so I need to send a start time of 2009-11-08 00:00:00 and an end time of 2009-11-08 23:59:59.

Here's a summary of my methodology:

// Retrieve the time now in UTC 
now := time.Now().UTC()

// Subtract two days from now 
twoDaysAgo := now.AddDate(0, 0, -2)

// Extract the day, month, and year individually, 
// which will be used to "rebuild" or "reset" our clock to 00:00:00
day, month, year := twoDaysAgo.Date()

// Build our start time using the extracted day, month, and year 
startTime := time.Date(year, month, day, 0, 0, 0, 0, time.UTC)

when startTime is printed, I expect to get 2009-11-08 00:00:00 but instead get 0014-05-02 00:00:00

Playground link

package main

import (
	"fmt"
	"time"
)

func main() {
	// we are trying to "reset the clock" on a specified date, 2 days in the past from today.
	// this time.Time will be used as a "start" timestamp for a request we want to make.

	// first, get the current time, which is hardcoded in Go Playground to be 2009-11-10 23:00:00, 
    // and prints the expected value
	now := time.Now().UTC()
	fmt.Println("Now:", now)

	// subtract two days, which should be 2009-11-08 23:00:00 and prints the expected value
	twoDaysAgo := now.AddDate(0, 0, -2)
	fmt.Println("Two days ago:", twoDaysAgo)

	// extract the day, month, and year from twoDaysAgo, which should be 2009 November 8
	// this prints the expected values so we can confirm that day, month, and year each contain what we need
	day, month, year := twoDaysAgo.Date()
	fmt.Println("Extracted day, month, and year:", day, month, year)

	// create a new time.Time using time.Date() so we can "reset" the clock to 00:00:00
	// we use day, month, and year extracted earlier as parameters to achieve this.
	// this prints a wildly inaccurate date of 0014-05-02 00:00:00 for a reason I don't understand.
	dateFromDateExtraction := time.Date(year, month, day, 0, 0, 0, 0, time.UTC)
	fmt.Println("This date is weird: ", dateFromDateExtraction)

	// if instead we hardcode the parameters for time.Date(),
	// the result is what you expect and this prints 2009-11-08 00:00:00
	dateHardcoded := time.Date(2009, time.November, 8, 0, 0, 0, 0, time.UTC)
	fmt.Println("This date appears as expected: ", dateHardcoded)
}

答案1

得分: 0

你已经颠倒了Date()的返回值。应该是这样的:

year, month, day := twoDaysAgo.Date()
英文:

You've reversed the return values from Date(). It should be this:

year, month, day := twoDaysAgo.Date()

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  • 本文由 发表于 2022年11月4日 07:59:46
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