英文:
How to check if a string contain 2 same char in a row?
问题
我有一个正则表达式，像这样：
REGEX_2_SAME_CHARACTER_IN_A_ROW = "^(?:(.)(?!\\))*$"
并且使用该正则表达式检查密码是否包含连续两个相同的字符：
contain2SameCharacterInARow, err := regexp.MatchString(REGEX_2_SAME_CHARACTER_IN_A_ROW, password)
但是我得到了这个错误：
error match regex 2 same char in a row: error parsing regexp: invalid or unsupported Perl syntax: `(?!`
我已经阅读了其他问题，其中使用了regexp.MustCompile，但我不知道如何处理或编写代码，有人可以帮我解决吗？
你可以在这里查看我用于验证密码的完整代码：
https://play.golang.com/p/5Fj4-UPvL8s
英文:
I have a regex like this
REGEX_2_SAME_CHARACTER_IN_A_ROW = "^(?:(.)(?!\\))*$"
and check password with that regex if it contain 2 same character in a row
contain2SameCharacterInARow, err := regexp.MatchString(REGEX_2_SAME_CHARACTER_IN_A_ROW, password)
but I get this error
error match regex 2 same char in a row: error parsing regexp: invalid or unsupported Perl syntax: `(?!`
I have read other question that using regexp.MustCompile but I don't know how to handle or code it, is there anyone can help me with the solution?
Here you can check my full code for validate password
https://play.golang.com/p/5Fj4-UPvL8s
答案1
得分: 1
你不需要锚点、非捕获组或负向先行断言。只需匹配并捕获任何字符 ((.))，然后跟随它自己 (\\1)。
REGEX_2_SAME_CHARACTER_IN_A_ROW = "(.)\\1"
但这引出了下一个问题：Go 正则表达式不支持反向引用，所以你需要找到另一种解决方案。一种解决方案是自己循环遍历字符串。
以下是一个使用简单循环的解决方案：
package mainimport ("errors""fmt""strings")func main() {fmt.Println(ValidatePassword("passsword01"))}func ContainsRepeatedChar(s string) bool {chars := strings.Split(s, "")char := chars[0]for i := 1; i < len(chars); i++ {if chars[i] == char {return true}char = chars[i]}return false}func ValidatePassword(password string) error {contain2SameCharacterInARow := ContainsRepeatedChar(password)if contain2SameCharacterInARow {fmt.Println("duplicated char")return errors.New("invalid password")}fmt.Println("all good")return nil}
希望对你有所帮助！
英文:
You don't need the anchor, the non-capturing group, nor the negative lookahead. Simply match and capture any character ((.)) followed by itself (\\1).
REGEX_2_SAME_CHARACTER_IN_A_ROW = "(.)\"
But this brings us to the next problem: Go regexes do not support back references, so you need to find a different solution. One would be looping the string yourself.
Here's a solution with a simple loop:
package mainimport ("errors""fmt""strings")func main() {fmt.Println(ValidatePassword("passsword01"))}func ContainsRepeatedChar(s string) bool {chars := strings.Split(s, "")char := chars[0]for i := 1; i < len(chars); i++ {if (chars[i] == char) {return true}char = chars[i]}return false}func ValidatePassword(password string) error {contain2SameCharacterInARow := ContainsRepeatedChar(password)if contain2SameCharacterInARow {fmt.Println("duplicated char")return errors.New("invalid password")}fmt.Println("all good")return nil}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论