Golang:如何将一个由字符串和数字组成的整数数组求和

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英文:

Golang: how to sum an array of integers as strings and numbers

问题

如何在GoLang中对包含字符串和数字混合类型的整数数组求和?

下面的代码出现错误:"mismatched types int and any" 和 "cannot initialize 1 variables with 2 values"。

是否有类似JavaScript解决方案的方法?
https://stackoverflow.com/questions/57893236/function-that-sums-array-numbers-including-numbers-as-strings

错误的代码:

import (
"fmt"
"strconv"
)

func main() {
  fmt.Println(sum([]any{9, 1, "8", "2"})) // 这应该输出20
}

func sum(arr []any) int {
  n:=0
  for _, v := range arr{
    temp:=strconv.Atoi(v) // 错误:无法用2个值初始化1个变量
    n+=temp // 错误:类型不匹配 int 和 any
  }
  return n
}

这个也会出错:

  n:=0
  for _, v := range arr{
    temp:=0
    if reflect.TypeOf(v)=="string"{
      temp=strconv.Atoi(v)
    } else {
      temp=v
    }
    n+=temp
  }
  return n
英文:

How to sum an array of integers with mixed types of strings and numbers in GoLang?
Code below errors with "mismatched types int and any" and "cannot initialize 1 variables with 2 values".

Is there something like this JavaScript solution?
https://stackoverflow.com/questions/57893236/function-that-sums-array-numbers-including-numbers-as-strings

errored code:

import (
"fmt"
"strconv"
)

func main() {
  fmt.Println(sum([]any{9, 1, "8", "2"})) // this should output 20
}

func sum(arr []any) int {
  n:=0
  for _, v := range arr{
    temp:=strconv.Atoi(v) //err: cannot initialize 1 variables with 2 values
    n+=temp //err: mismatched types int and any
  }
  return n
}

This also errors:

  n:=0
  for _, v := range arr{
    temp:=0
    if reflect.TypeOf(v)=="string"{
      temp=strconv.Atoi(v)
    } else {
      temp=v
    }
    n+=temp
  }
  return n

</details>


# 答案1
**得分**: 4

使用[type switch](https://go.dev/ref/spec#Type_switches)来适当处理整数和字符串值。

`temp:=strconv.Atoi(v)`返回两个值。将结果分配给两个变量。处理错误返回。

以下是修复后的代码:

```go
func sum(arr []any) int {
    n := 0
    for _, v := range arr {
        switch v := v.(type) {
        case int:
            n += v
        case string:
            i, err := strconv.Atoi(v)
            if err != nil {
                panic(err)
            }
            n += i
        default:
            panic(fmt.Sprintf("unsupported type %T", v))
        }
    }
    return n
}

为了完整起见,这里还有一个使用反射的版本的函数。但是,推荐使用类型切换版本的函数。

func sum(arr []any) int {
    n := 0
    for _, v := range arr {
        v := reflect.ValueOf(v)
        if v.Kind() == reflect.Int {
            n += int(v.Int())
        } else if v.Kind() == reflect.String {
            i, err := strconv.Atoi(v.String())
            if err != nil {
                panic(err)
            }
            n += i
        } else {
            panic(fmt.Sprintf("unsupported type %s", v.Type()))
        }
    }
    return n
}
英文:

> count+=temp //err: mismatched types int and any

Use a type switch to handle integer and string values as appropriate.

> temp:=strconv.Atoi(v) //err: cannot initialize 1 variables with 2 values

strconv.Atoi returns two values. Assign the result to two variables. Handle the error return.

Here's the code with the fixes:

func sum(arr []any) int {
	n := 0
	for _, v := range arr {
		switch v := v.(type) {
		case int:
			n += v
		case string:
			i, err := strconv.Atoi(v)
			if err != nil {
				panic(err)
			}
			n += i
		default:
			panic(fmt.Sprintf(&quot;unsupported type %T&quot;, v))
		}
	}
	return n
}

For completeness, here's a version of the function that uses reflection. The type switch version of the function is preferred over reflection.

func sum(arr []any) int {
	n := 0
	for _, v := range arr {
		v := reflect.ValueOf(v)
		if v.Kind() == reflect.Int {
			n += int(v.Int())
		} else if v.Kind() == reflect.String {
			i, err := strconv.Atoi(v.String())
			if err != nil {
				panic(err)
			}
			n += i
		} else {
			panic(fmt.Sprintf(&quot;unsupported type %s&quot;, v.Type()))
		}
	}
	return n
}

huangapple
  • 本文由 发表于 2022年10月31日 09:02:00
  • 转载请务必保留本文链接:https://go.coder-hub.com/74257846.html
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