英文:
what is difference between *[] *types.a and [] *types.b in golang
问题
在上述代码中，函数声明如下：
func (c *Congress) Finalize(chain consensus.ChainHeaderReader, header *types.Header, state *state.StateDB, txs *[]*types.Transaction, uncles []*types.Header, receipts *[]*types.Receipt, systemTxs []*types.Transaction) error {
其中，txs *[]*types.Transaction 和 uncles []*types.Header 是两个参数。在Go语言中，这两个参数的含义如下：
-
txs *[]*types.Transaction：这是一个指向[]*types.Transaction类型的指针。[]*types.Transaction表示一个指向types.Transaction类型的切片。因此，txs是一个指向types.Transaction类型切片的指针。 -
uncles []*types.Header：这是一个[]*types.Header类型的切片。[]*types.Header表示一个指向types.Header类型的切片。因此，uncles是一个types.Header类型切片。
希望以上解释对你理解Go语言中的术语有所帮助。
英文:
while looking into code I found below function declaration
func (c *Congress) Finalize(chain consensus.ChainHeaderReader, header *types.Header, state *state.StateDB, txs *[]*types.Transaction, uncles []*types.Header, receipts *[]*types.Receipt, systemTxs []*types.Transaction) error {
where two parameters are txs *[]*types.Transaction, uncles []*types.Header, what does it mean in terms of golang
just want to understand golang terminology with reference to above code
答案1
得分: 0
uncles []*types.Header
uncles是一个切片。如果你将它复制到其他地方（例如通过将其作为函数参数传递），对它的更新不会向原始切片传播（有一个细微差别，即对元素的更改会传播，但原始切片的大小/数据指针将保持不变）。
txs *[]*types.Transaction
txs是一个指向切片的指针。它有点像一个“引用”，因为对所指向的切片的更新会传播到指向该切片的其他地方。因此，如果将一个指向切片的指针作为函数参数传递，函数可能会更改所指向的切片的属性（添加/删除元素）。
英文:
uncles []*types.Header
uncles is slice. If you copy it somewhere (perhaps by passing it in as a function parameter) updates to it will not propagate backwards to the original (with the nuance that changes to elements will propagate, but the size/data pointer of the original will remain unchanged).
txs *[]*types.Transaction
txs is a pointer to a slice. It’s sort of like a “reference” in that updates to the slice pointed at propagate to anyone else pointing to that slice. So if you pass a pointer to a slice as a function parameter, the function may change the properties of the slice pointed to (adding/removing elements).
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