return json parsed output in for loop in golang

huangapple
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英文:

return json parsed output in for loop in golang

问题

你想从这个函数中返回下面的JSON响应output，以便在另一个函数中使用返回的值。但是在for循环中你无法这样做，有没有解决办法呢？

我看到了一些解决方案，但不太清楚如何将下面的JSON字符串fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Phone.Mobile, p.INTaddress.Email, p.Phone.Carrier, p.Address.City)赋值给一个切片。

英文:

i want to return the below json response output from this function, so i can use that returned value in another function.
but in the for loop i cant able to do that
is there any solution for this.

  1. func Search_num(mobilenumber string) {
  3. 	//.......get request.......
  5. 	body, err := io.ReadAll(search_res.Body)
  6. 	if err != nil {
  7. 		log.Fatalln(err)
  8. 	}
  9. 	defer search_res.Body.Close()
  11. 	var jsonbody Response
  13. 	if err := json.Unmarshal(body, &jsonbody); err != nil {
  14. 		log.Fatalln(err)
  15. 	}
  17. 	for _, p := range jsonbody.Data {
  18. 		output := fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Phone.Mobile, p.INTaddress.Email, p.Phone.Carrier, p.Address.City)
  20. 		
  21. 	}
  23. 	return output
  25. }

seen some solutions but didnt understood how to assign the below json fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Phone.Mobile, p.INTaddress.Email, p.Phone.Carrier, p.Address.City) in a slice return json parsed output in for loop in golang

答案1

得分: 2

像这样，在for循环中不使用:=，而是使用=。并且for循环看起来是不需要的，只需根据需要使用jsonbody.Data[0]或jsonbody.Data[len(jsonbody.Data)-1]。

func Search_num(mobilenumber string) {

  1. //.......获取请求.......
  3. body, err := io.ReadAll(search_res.Body)
  4. if err != nil {
  5.     log.Fatalln(err)
  6. }
  7. defer search_res.Body.Close()
  9. var jsonbody Response
  11. if err := json.Unmarshal(body, &jsonbody); err != nil {
  12.     log.Fatalln(err)
  13. }
  15. var output string
  16. for _, p := range jsonbody.Data {
  17.     output = fmt.Sprintf("姓名：%s\n手机号：%s\n电子邮件：%s\n运营商：%s\n城市：%s\n", p.Name, p.Phone.Mobile, p.INTaddress.Email, p.Phone.Carrier, p.Address.City)
  18.     
  19. }
  21. return output

}

英文:

like this, output not use := in the for range, just use = 。 and for loop sees not need, just you demand use jsonbody.Data[0] or jsonbody.Data[len(jsonbody.Data)-1]

func Search_num(mobilenumber string) {

  1. //.......get request.......
  3. body, err := io.ReadAll(search_res.Body)
  4. if err != nil {
  5.     log.Fatalln(err)
  6. }
  7. defer search_res.Body.Close()
  9. var jsonbody Response
  11. if err := json.Unmarshal(body, &jsonbody); err != nil {
  12.     log.Fatalln(err)
  13. }
  15. var output string
  16. for _, p := range jsonbody.Data {
  17.     output = fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Phone.Mobile, p.INTaddress.Email, p.Phone.Carrier, p.Address.City)
  18.     
  19. }
  21. return output

}

答案2

得分: 0

如果我理解正确，你有一个格式为json的数据：

  1. [
  2.   {"name" : "name1", "mobile": "123", "email": "email1@example.com", "carrier": "carrier1", "city", "city1"},
  3.   {"name" : "name2", "mobile": "1234", "email": "email2@example.com", "carrier": "carrier2", "city", "city2"}
  4.   ...
  5. ]

你想要在这个数据中搜索，找到对应的号码（例如1234），并返回整个结构，使用你的Sprintf进行格式化。

如果你的Response结构体如下所示：

  1. type Response struct {
  2.   Name string
  3.   Mobile string
  4.   Email string
  5.   Carrier string
  6.   City string
  7. }

那么你需要将它们提供给Unmarshaler来获取它们。像这样：

  1. func Search_num(mobilenumber string) string {
  3.     //.......获取请求.......
  5.     body, err := io.ReadAll(search_res.Body)
  6.     if err != nil {
  7.         log.Fatalln(err)
  8.     }
  9.     defer search_res.Body.Close()
  11.     var responses []Response
  13.     if err := json.Unmarshal(body, &responses); err != nil {
  14.         log.Fatalln(err)
  15.     }
  17.     for _, p := range responses {
  18.         if p.Mobile == mobilenumber {
  19.             return fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Mobile, p.Email, p.Carrier, p.City)
  20.         }
  21.     }
  23.     return mobilenumber+" not found"
  24. }
英文:

If I get this correctly you have a json of the format:

  1. [
  2.   {"name" : "name1", "mobile": "123", "email": "email1@example.com", "carrier": "carrier1", "city", "city1"},
  3.   {"name" : "name2", "mobile": "1234", "email": "email2@example.com", "carrier": "carrier2", "city", "city2"}
  4.   ...
  5. ]

which you would like to search through, find the number (eg 1234) and return the whole struct formatted using your Sprintf

If your Response struct is like:

  1. type Response struct {
  2.   Name string
  3.   Mobile string
  4.   Email string
  5.   Carrier string
  6.   City string
  7. }

Then you need to provide a slice of those into the Unmarshaler to get them back. Like:

  1. func Search_num(mobilenumber string) string {
  3.     //.......get request.......
  5.     body, err := io.ReadAll(search_res.Body)
  6.     if err != nil {
  7.         log.Fatalln(err)
  8.     }
  9.     defer search_res.Body.Close()
  11.     var responses []Response
  13.     if err := json.Unmarshal(body, &responses); err != nil {
  14.         log.Fatalln(err)
  15.     }
  17.     for _, p := range responses {
  18.         if p.Mobile == mobilenumber {
  19.             return fmt.Sprintf("Name : %s\nMobile : %s\nEmail : %s\nCarrier : %s\nCity : %s\n", p.Name, p.Mobile, p.Email, p.Carrier, p.City)
  20.         }
  21.     }
  23.     return mobilenumber+" not found"
  24. }

huangapple
  • 本文由 发表于 2022年10月9日 18:30:48
  • 转载请务必保留本文链接：https://go.coder-hub.com/74003977.html
  • api
  • go
  • json
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