英文:
Should I use synchronization for visibility of a single pointer?
问题
根据参考文献，它说：
> 否则，对于单字大小或子字大小的内存位置的每次读取，必须观察到实际写入该位置的值（可能是由并发执行的goroutine写入的），并且尚未被覆盖。
由于指针的大小与一个字相同，这是否意味着仅仅为了可见性而不需要同步呢？
英文:
As per the reference, it says
> Otherwise, each read of a single-word-sized or sub-word-sized memory location must observe a value actually written to that location (perhaps by a concurrent executing goroutine) and not yet overwritten.
Since a pointer is word-sized, does that mean synchronization is not necessary for mere purpose of visiblity?
答案1
得分: 1
不，可见性意味着当一个goroutine写入一个变量时，其他goroutine可以看到这个变化。因此，可见性需要同步。否则，一个读取的goroutine可能会看到变量的旧值（未更新）。
英文:
No, visibility means that when one goroutine writes to a variable, other goroutines see the change. So, visibility requires synchronization. Otherwise a reading goroutine will possibly see a stale (not updated) value of the variable.
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