英文:
scanning a string separated by ":" in golang
问题
我已经将您提供的内容翻译成中文，如下所示：
type Origin struct {
Lat float64 `json:"lat" binding:"required"`
Lng float64 `json:"lng" binding:"required"`
Address string `json:"address" binding:"required"`
Name string `json:"name" binding:"required"`
}
func (o *Origin) ParseString(str string) error {
if str == "" {
return nil
}
_, err := fmt.Sscanf(str, "%f:%f:%[^:]:%[^/n]", &o.Lat, &o.Lng, &o.Address, &o.Name)
if err != nil {
return fmt.Errorf("parsing origin: %s, input:%s", err.Error(), str)
}
return nil
}
func main() {
o := &Origin{}
o.ParseString("23.584950:58.353603:an address, str:a place, name")
fmt.Println(o)
}
然而，结构体o打印出的结果是：&{23.58495 58.353603 }。地址和名称没有被正确地扫描。请问在Sscanf中应该使用什么正确的格式来正确解析这个字符串？
英文:
I need to string scan 23.584950:58.353603:an address, str:a place, name
into :
type Origin struct {
Lat float64 `json:"lat" binding:"required"`
Lng float64 `json:"lng" binding:"required"`
Address string `json:"address" binding:"required"`
Name string `json:"name" binding:"required"`
}
My code:
package main
import "fmt"
type Origin struct {
Lat float64 `json:"lat" binding:"required"`
Lng float64 `json:"lng" binding:"required"`
Address string `json:"address" binding:"required"`
Name string `json:"name" binding:"required"`
}
func (o *Origin) ParseString(str string) error {
if str == "" {
return nil
}
_, err := fmt.Sscanf(str, "%f:%f:%[^:]:%[^/n]", &o.Lat, &o.Lng, &o.Address, &o.Name)
if err != nil {
return fmt.Errorf("parsing origin: %s, input:%s", err.Error(), str)
}
return nil
}
func main() {
o := &Origin{}
o.ParseString("23.584950:58.353603:address, text:place, name, text")
fmt.Println(o)
}
https://go.dev/play/p/uUTNyx2cDFB
However, struct o prints out: &{23.58495 58.353603 }. Address and name are not scanned properly. What is the correct format to be used in Sscanf to parse this string correctly?
答案1
得分: 2
你正在使用正则表达式来捕获输入，同时使用fmt.Scanff。fmt.Scanff不支持正则表达式。如果你想使用正则表达式，可以使用regexp包。
或者你可以使用简单的strings.Split函数将输入解析为正确的类型：
func (o *Origin) ParseString2(str string) error {
if str == "" {
return nil
}
parts := strings.Split(str, ":")
if len(parts) != 4 {
return errors.New("expected format '...:...:...:...'")
}
f, err := strconv.ParseFloat(parts[0], 64)
if err != nil {
return err
}
o.Lat = f
f, err = strconv.ParseFloat(parts[1], 64)
if err != nil {
return err
}
o.Lng = f
o.Address = parts[2]
o.Name = parts[3]
return nil
}
英文:
You are using a regex to capture input, while using fmt.Scanff. fmt.Scanff does not support RegEx. If you want to use regex, use the regexp package.
Or you could use a simple strings.Split and parse the input to the correct type:
func (o *Origin) ParseString2(str string) error {
if str == "" {
return nil
}
parts := strings.Split(str, ":")
if len(parts) != 4 {
return errors.New("expected format '...:...:...:...")
}
f, err := strconv.ParseFloat(parts[0], 64)
if err != nil {
return err
}
o.Lat = f
f, err = strconv.ParseFloat(parts[1], 64)
if err != nil {
return err
}
o.Lng = f
o.Address = parts[2]
o.Name = parts[3]
return nil
}
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