英文:
unmarshall simple json data with golang
问题
以下是翻译好的内容：
以下程序为我提供了所需的输出（ccc09e）。但是这种方法是否正确或者是否可以改进呢？
package mainimport ("encoding/json""fmt")type People struct {Name string}func main() {empJson := `[{"name":"ccc09e"}]`var emp []Peoplejson.Unmarshal([]byte(empJson), &emp)s := fmt.Sprintf("%v", emp[0])s = s[1 : len(s)-1]fmt.Println(s)}
我得到了所需的输出 https://go.dev/play/p/L2IJp-ehA2S ，但我需要改进这个程序。
英文:
https://go.dev/play/p/L2IJp-ehA2S
The following program provides me the required output (ccc09e). But this is correct approach or this can be improved.
package mainimport ("encoding/json""fmt")type People struct {Name string}func main() {empJson := `[{"name":"ccc09e"}]`var emp []Peoplejson.Unmarshal([]byte(empJson), &emp)s := fmt.Sprintf("%v", emp[0])s = s[1 : len(s)-1]fmt.Println(s)}
I got the required output https://go.dev/play/p/L2IJp-ehA2S and I need improvement to the program.
答案1
得分: 1
看起来你想要获取s中People数组的第一个元素的Name。
不需要进行字符串操作，直接访问即可。
package mainimport ("encoding/json""fmt")type People struct {Name string}func main() {empJson := `[{"name":"ccc09e"}]`var emp []Peoplejson.Unmarshal([]byte(empJson), &emp)s := emp[0].Namefmt.Println(s)}
https://go.dev/play/p/O2hiGuSyM53
英文:
Looks like you want the Name of the First element of People array in s
No need to do string manipulations. Just access it directly
package mainimport ("encoding/json""fmt")type People struct {Name string}func main() {empJson := `[{"name":"ccc09e"}]`var emp []Peoplejson.Unmarshal([]byte(empJson), &emp)s := emp[0].Namefmt.Println(s)}
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