String Interpolation / Templating Variables in Go lang

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英文:

String Interpolation / Templating Variables in Go lang

问题

假设我有以下字节字符串,表示一些 JSON 数据包:

data := []byte(`{
    "Id" : 1,
    "Name": "John Doe",
    "Occupation": "gardener"
}`)

我想知道,是否有一种动态创建这个 JSON 数据包的方法,例如:

var NAME = "John Doe"

var OCCUPATION = "gardener"

data := []byte(`{
    "Id" : 1,
    "Name": {{ NAME }},
    "Occupation": {{ OCCUPATION }}
}`)
英文:

Let's say I have the following byte string which represents some JSON packet:

data := []byte(`{
    "Id" : 1,
    "Name": "John Doe",
    "Occupation": "gardener"
}`)

I'm wondering, is there a way to create this JSON packet dynamically, e.g.,

var NAME = "John Doe"

var OCCUPATION = "gardener"

data := []byte(`{
    "Id" : 1,
    "Name": {{ NAME }},
    "Occupation": {{ OCCUPATION }}
}`)

答案1

得分: 3

你可以创建一个结构体并进行编组:

type Data struct {
   ID int `json:"Id"`
   Name string `json:"Name"`
   Occupation string `json:"Occupation"`
}

data := Data{ID: 1, Name: "name", Occupation: "Occupation"}

byteData, err := json.Marshal(data)

这样做也会在必要时处理数据中的转义字符。

另一种方法:

data := map[string]interface{}{
  "Id": id,
  "Name": name,
  "Occupation": Occupation,
}
byteData, err := json.Marshal(data)

你也可以使用模板来实现,但是如果输入字符串包含需要转义的字符,有可能生成无效的 JSON 数据。

英文:

You can create a struct and marshal it:

type Data struct {
   ID int `json:"Id"`
   Name string `json:"Name"`
   Occupation string `json:"Occupation"`
}

data:=Data{ ID:1, Name: "name", Occupation: "Occupation" }

byteData, err:=json.Marshal(data)

This will also take care of escaping characters in data when necessary.

Another way:

data:=map[string]interface{} {
  "Id": id,
  "Name": name,
  "Occupation": Occupation,
}
byteData, err:=json.Marshal(data)

You can also use templates for this, but then there is a chance you may generate invalid JSON data if the input strings contain characters that need to be escaped.

答案2

得分: 0

Go by Example网站上有一个关于使用encoding/json包的很好的页面:https://gobyexample.com/json

在你的特定情况下:

package main

import (
	"encoding/json"
	"log"
)

type Person struct {
	ID         int    `json:"Id"`
	Name       string `json:"Name"`
	Occupation string `json:"Occupation"`
}

func main() {

	p := Person{ID: 1, Name: "John Doe", Occupation: "gardener"}

	log.Printf("Person data: %+v\n", p)

	d, err := json.Marshal(p)
	if err != nil {
		log.Fatalf("failed to marshal json: %v", err)
	}

	log.Printf("Encoded JSON: %s\n", d)
}
2022/09/05 16:02:54 Person data: {ID:1 Name:John Doe Occupation:gardener}
2022/09/05 16:02:54 Encoded JSON: {"Id":1,"Name":"John Doe","Occupation":"gardener"}
英文:

Go by Example has a great page on using the encoding/json package: https://gobyexample.com/json

In your specific case:

package main

import (
	"encoding/json"
	"log"
)

type Person struct {
	ID         int    `json:"Id"`
	Name       string `json:"Name"`
	Occupation string `json:"Occupation"`
}

func main() {

	p := Person{ID: 1, Name: "John Doe", Occupation: "gardener"}

	log.Printf("Person data: %+v\n", p)

	d, err := json.Marshal(p)
	if err != nil {
		log.Fatalf("failed to marshal json: %v", err)
	}

	log.Printf("Encoded JSON: %s\n", d)
}
2022/09/05 16:02:54 Person data: {ID:1 Name:John Doe Occupation:gardener}
2022/09/05 16:02:54 Encoded JSON: {"Id":1,"Name":"John Doe","Occupation":"gardener"}

huangapple
  • 本文由 发表于 2022年9月5日 23:44:41
  • 转载请务必保留本文链接:https://go.coder-hub.com/73611848.html
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