I have this type of error while iterate arrary in for loop "panic: runtime error: index out of range"

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英文:

I have this type of error while iterate arrary in for loop "panic: runtime error: index out of range"

问题

package main
import (
    "fmt"
)
func main() {
    var a int
    var b int
    
    var ar []int
    fmt.Scan(&a)
    
    for i := 1; i < a; i++ {
        fmt.Scan(&b)
        ar[i] = b
    }
    
    fmt.Print("Hello")
    for i := a; i > 0; i-- {
        b = ar[i]
        fmt.Print(b)
    }
}
package main
import (
    "fmt"
)
func main() {
    var a int
    var b int
    
    var ar []int
    fmt.Scan(&a)
    
    for i := 1; i < a; i++ {
        fmt.Scan(&b)
        ar[i] = b
    }
    
    fmt.Print("Hello")
    for i := a; i > 0; i-- {
        b = ar[i]
        fmt.Print(b)
    }
}
英文:
package main
import (
    &quot;fmt&quot;
)
func main() {
    var a int
    var b int
    
    var ar [] int
    fmt.Scan(&amp;a)
    
    for i:= 1; i&lt;a; i++ {
        fmt.Scan(&amp;b)
        ar[i] = b
    }
    
    fmt.Print(&quot;Hello&quot;)
    for i:= a; i&gt;0; i-- {
        b = ar[i]
        fmt.Print(b)
    }
}

答案1

得分: 1

修正后的代码,我认为这是你想要的:

package main

import (
	"fmt"
)

func main() {
	var a int
	var b int

	fmt.Scan(&a)

	// 创建长度为a、容量为a、填充为0的切片
	ar := make([]int, a, a)
	for i := 0; i < a; i++ {
		fmt.Scan(&b)
		ar[i] = b
	}

	fmt.Print("Hello")
	for i := a - 1; i >= 0; i-- {
		b = ar[i]
		fmt.Print(b)
	}
}

请注意,我只翻译了代码部分,其他内容不做翻译。

英文:

Corrected code, I think it's what you want

package main

import (
	&quot;fmt&quot;
)

func main() {
	var a int
	var b int

	fmt.Scan(&amp;a)

	// make slice with len a, cap a, 0 filled
	ar := make([]int, a, a)
	for i := 0; i &lt; a; i++ {
		fmt.Scan(&amp;b)
		ar[i] = b
	}

	fmt.Print(&quot;Hello&quot;)
	for i := a - 1; i &gt;= 0; i-- {
		b = ar[i]
		fmt.Print(b)
	}
}

答案2

得分: 0

对于 i:= 1; i&lt;a; i++ {
        fmt.Scan(&amp;b)
        ar[i] = b
    }

ar 是空的。如果你想添加一些内容,可以使用 ar = append(ar, ...)

或者使用正确大小创建 arar = make(int[], a)。然后 ar 将包含多个零值。

英文:
for i:= 1; i&lt;a; i++ {
        fmt.Scan(&amp;b)
        ar[i] = b
    }

ar is empty. If you want to add something, then use ar = append(ar, ...)

Or create ar with the correct size: ar = make(int[], a). Then ar will contain several zero values.

答案3

得分: 0

2个可能的解决方案。一个是利用数组,另一个是利用切片

何时使用数组(当您知道数组的确切大小时):

将数组声明为ar := make([]int, a),其中a是数组的大小。


何时使用切片(当您不确定确切大小或可能需要扩展时):

像这样将元素追加到数组中:ar = append(ar, b)

英文:

2 possible solution. 1 making use of an array the other making use of a slice

When to use an array (When u know the exact size of your array):

Declare your array as ar := make([]int, a) this assume size of array is a


When to use slice (When u are not sure of the exact size or it may be expanded):

Append to your array like this: ar = append(ar, b)

huangapple
  • 本文由 发表于 2022年8月17日 18:50:10
  • 转载请务必保留本文链接:https://go.coder-hub.com/73387179.html
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